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Nataly_w [17]
3 years ago
13

X/4 · ___ = x. A)-4 B)0 C)1/4 D)4

Mathematics
1 answer:
castortr0y [4]3 years ago
8 0
The answer is choice D) 4

(x/4) times 4 = x

You can think of it as 
(1/4) times 4 = 1
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Suppose the contact rate for a phone survey is 78% and that 22% of people will participate in that survey. Assume that agreeing
Gnoma [55]
Remember that, for independent events, the probability that both occurr is the product of the individual probabilities.

a) Probability of being contacted: 78% = 0.78

Probaility of refusing: 1 - 22% = 1 -0.22 = 0.78

Combined probability: 0.78*0.78 = 0.6084

b) The probability of failing to contact or making contact and not geeting them to agree 1 - the probability of contacting and getting them to agree.

The probabilityof contacting and getting them to agree is 0.78*0.22 = 0.1716

The the answer to this question is 1 - 0.1716 = 0.8284


 
8 0
3 years ago
1. (2 points) Solve each equation and write the answer on the line
BARSIC [14]
Eighteen tens < 21 × (5+5)

Hope this helps!
7 0
3 years ago
Ana escribe conjuntos de cinco enteros positivos consecutivos con la siguiente propiedad: La suma de tres de los números es tan
Keith_Richards [23]

Answer:

a) 1.

Step-by-step explanation:

Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.

Luego, el conjunto de los cinco enteros positivos se puede expresar como

A = {a; a+1; a+2; a+3; a+4}

Dada la condición del problema, se debe cumplir que

a + (a+1) + (a+2) = (a+3) + (a+4)

⇒  3a + 3 = 2a + 7

Resolviendo la ecuación resulta

a = 4

Luego, el conjunto A nos resulta

A = {4; 5; 6; 7; 8}

Puede concluirse que sólo un conjunto cumple con esta condición.

5 0
3 years ago
Plz help! Will mark brainliest if correct! No links please
joja [24]

Answer:

20.8

Step-by-step explanation:

hope this helps

8 0
3 years ago
What x value solves this equation? 3x-5=1
horrorfan [7]

Answer:

x=2

Step-by-step explanation:

Add 5 to each side.

3x-5+5=1+5

3x=6

Divide each side by 3.

Your answer would be x=2.

3 0
3 years ago
Read 2 more answers
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