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2 years ago

Evaluate the expression. -1 x ( 1-(negitive 7 to the 2 power))

Mathematics

1 answer:

dmitriy555 [2]2 years ago

6 0

Answer:

-50x

Step-by-step explanation:

−1x ( 1 − ( 7²) )

= ( − 1x ) ( 1 + 49 )

= ( −1x ) ( 1 ) + ( −1x ) ( 49 )

= −x − 49x

= −50x

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Which table represents a linear function?

Natali5045456 [20]

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$The \: \: third \: \: table.$

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3 years ago

Divide...................

LuckyWell [14K]

Answer:

Exact form 9/4 Mixed number form 2 1/4 decimal form 2.25

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Shipping rates for Company A and Company B are shown in the tables below. Which company has shipping rates that you can represen

meriva

Company B; the ratios of cost to weight are equivalent.

Step-by-step explanation:

Step 1:

In the equation, $y=kx$ k is the constant of proportionality.

If the values are in accordance with $y=kx$ , the values of k will be constant for all the values.

So we determine the values of k for both the companies and see which has a constant k.

If $y=kx, k = \frac{y}{x}$ . In these tables, y is the total cost and x is the weight in lbs.

Step 2:

For company A,

when $y=10.55, x=1, k = \frac{10.55}{1} = 10.55,$

when $y=10.85, x=2, k = \frac{10.85}{2} = 5.425,$

when $y=11.15, x=3, k = \frac{11.15}{3} = 3.71666.$

For company B,

when $y=2.75, x=1, k = \frac2.75}{1} = 2.75,$

when $y=5.50, x=2, k = \frac{5.50}{2} = 2.75,$

when $y=8.25, x=3, k = \frac{8.25}{3} = 2.75.$

So company B has a constant value of $k=2.75$ .

3 0

3 years ago

HELP! 8TH GRADE MATH PLS LOL

LekaFEV [45]

<h2><u>Given</u><u>:</u><u>-</u></h2>

${ \large{➢ \: \: \bf{x = - 8}}}$

<h2><u>Solution</u><u>:</u><u>-</u></h2>

${ \large{➢ \: \: \bf{ \dfrac{2y}{3} = 3 \times - 8 + 34}}}$

${ \large{➢ \: \: \bf{ \dfrac{2y}{3} = - 24 + 34}}}$

${ \large{ \bf{ ➢ \: \: \cancel{2}y = 3 \times { \cancel{(10)} {} \: \: ^{5} }}}}$

${ \large{ \therefore{ \bf{y = 15 \: \: Ans.}}}}$

3 0

3 years ago

Can somebody please help me with question b please?

snow_tiger [21]

$\bf A=
\begin{bmatrix}
-2&0\\1&3
\end{bmatrix}\qquad B=
\begin{bmatrix}
1&0&3\\-1&3&0
\end{bmatrix}\\\\
-----------------------------\\\\
AB=
\begin{bmatrix}
(-2\cdot 1)+(0\cdot -1)&(-2\cdot 0)+(0\cdot 3)&(-2\cdot 3)+(0\cdot 0)\\\\
(1\cdot 1)+(3\cdot -1)&(1\cdot 0)+(3\cdot 3)&(1\cdot 3)+(3\cdot 0)
\end{bmatrix}$

as you notice above, is the first-row components from A, multiplying all the columns subsequently on B, and you add the products of that row, that gives you one component on the AB matrix

in the one above, we end up with a 2x3 AB matrix

4 0

3 years ago