The rule we'll use is
p^(q*r) = (p^q)^r
The exponents have been rearranged a bit.
In this case, p = 3.14, q = 159 and r = x, so,
p^(q*r) = (p^q)^r
3.14^(159*x) = (3.14^159)^x
This is in the form A^x with A = 3.14^159
Answer:
it's the square root of 63 and I'd assume rounding to the tenth but I dont know how ur teacher does it.
Step-by-step explanation:
find a calculator if u have one then solve for the square root of 63. this method is called the pythagorean theorem that i used
<span>x(x+2)+x(x-3)
=x^2 + 2x + x^2 - 3x
= 3x^2 - x</span>
Give the number a name. You can call it anything. I'll call it ' G '.
The square of the number is G² .
91 more than that is G² + 91 .
