Okay YAS, I loove linear equations... moving on.
OKAY, so I'm going to start with Q2 (not 100% sure how to work out 1, but lets use process of elimination). Firstly, the rule is y=mx+c So, start with the first line y=2x-3, from this the first thing you need to do is find the y-intercept (m) and the gradient (c). So, this is very simple 2 is m and -3 is c (if you look at the rule it matches up).
m=2/1(this is rise/run, rise is how much you go up by, and run is how much you go left or right by (left if positive, right if negative))
c=-3
Now, go to your graph, and look on the y line and go to -3. Then go left, 1, and up 2. IS THERE A LINE CROSSING THROUGH THIS POINT? Yes? Good.
Now for y=-1/2+1. Looking at the rule again (y=mx+c),
m=-1/2 (rise/run)
c=1
NOW, once again go to your graph, and look on the y line and go to 1 (in this case the line actually passes through this point), now go right 2 places and up 1. IS THERE A LINE? Yes? Good!
NOOOW, for Q3, use the same steps and you will have the answer.
y=1/4x-2
m=1/4 (rise/run)
c=-2
Look at graph C, start at -2 on the y line, go left 4, and up 1? Yes? Line crossing through this point? good!!
Now for the 2nd one,
y= -2/5x+4
m=-2/3
c=4
Look at the same graph start at 4 on the y line, go right 5 and up 2! Got it? There's a line crossing through this point, yes? YAY
Now I have no idea how to do Q1, but by process of elimination it's pretty obvious. I hope this is right! Okay, bye!! :D
Answer:
C
Step-by-step explanation:
Trust Bro
Answer:
y=-2+4
Step-by-step explanation:
we know the y intercept is four, so we can plug that into y=mx+b
so far we know y=mx+4
and the equation for finding slope is 
so let's find two points on the graph
let's make it easy on ourselves and use the points laid out for us
(0,4) and (2,0)
solving that would come out to be 
simplified, that would be -2
now that we know the slope, we can put them into slope-intercept form
y=-2+4
3x - 2y - 7x + y
Rearrange the terms
3x - 7x - 2y + y
Add like terms
-4x - y
