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aleksley [76]
3 years ago
11

I need help finding the side AB NOT THE ANGE AB which is 90°

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

Answer:

AB = 10.83 cm

Step-by-step explanation:

From ΔABC,

m∠B = 90°

By applying sine rule in the given triangle,

sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}

sin(37°) = \frac{AB}{AC}

AB = AC(sin37°)

AB = 18×(0.060182)

     = 10.833

     ≈ 10.83 cm

Therefore, AB = 10.83 cm is the answer.

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PLS HELP WITH THISS!!! I WILL GIVE BRAINLIEST
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Answer:

D&B

Step-by-step explanation:

turn 6 to a fraction which is 6/1

So you keep the first fraction the same

change the division sign to a multiplication sign

change 3/4 to 4/3

so 6/1x4/3

multiply straight across the top and bottom

you get 24/3

simplified is 1/8lbs

5 0
3 years ago
Application Question:
Alika [10]
When you add 4 to 25 you get 21 then subtract 11 and get 10 and then add 15 which is equal to 25 and then subtract 13.

the answer is 12
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let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

4 0
1 year ago
in solving the equation for x to distribute a minus 4 on one side of the equation what needs to be done on the other side of the
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The distributive property is a simplification rule that does not change the value of an expression. Nothing need be done to the other side of the equation.

q = -4(3+x)
q = -4*3 -4*x . . . . . the -4 is distributed. The right side has not changed value.
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One number is four times another number. If their sum is 95, what are the numbers?
nikdorinn [45]
Let x be one number and y be the other.

#1 - Set up a system of equations.
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#2 - Solve the system by substitution.
x + (4x) = 45
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(9) + y = 45
y = 36
8 0
4 years ago
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