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Vsevolod [243]
3 years ago
6

What is an equation of the line that passes through the point (2,-3) and is perpendicular to the line 2x+5y=10?

Mathematics
1 answer:
inessss [21]3 years ago
6 0
<h3>Answer:  5x-2y = 16</h3>

===============================================

Explanation:

Consider the standard form Ax+By = C

Anything perpendicular to this is Bx-Ay = D. We swapped the positions of A and B, and changed the plus sign to a minus. This will ensure we get a negative reciprocal slope needed for the perpendicular line. The slope of the first line is -B/A, while the slope of the second line is A/B. The two slopes multiply to -1 assuming neither A nor B are zero.

Also, I've introduced the constant D. There may be cases when C = D, but that isn't always the case.

The given equation is 2x+5y = 10. This tells us A = 2, B = 5, C = 10.

The perpendicular line will be of the form 5x-2y = D, based on the template I mentioned above.

Plug the coordinates (2,-3) into 5x-2y = D to find the value of D

5x-2y = D

5(2)-2(-3) = D

10+6 = D

16 = D

D = 16

So 5x-2y = D updates to 5x-2y = 16

Therefore, 5x-2y = 16 is perpendicular to the original line, and this new line goes through (2,-3)

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Into how many equal parts can the same cake be cut if the cuts can only be made along the gridlines, cake can be cut into 20 equal parts.

This is further explained below.

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