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Ludmilka [50]
3 years ago
8

Can someone help me pleaseshow your work

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

a.

l = 2w - 3

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How many factors does the following term have -9xyz
madreJ [45]

Answer:

4

Step-by-step explanation:

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3 years ago
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What is the volume of this rectangular prism if the side of each square is 1 cm?
aliina [53]
Your answer is B because it’s 6 times 3 times 4 and you add cubic because it’s volume.
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3 years ago
How many solutions do these equations have
Arlecino [84]

Answer:

\large\boxed{\bold{one\ solution}\ (1,\ -4)\to x=1,\ y=-4}

Step-by-step explanation:

\left\{\begin{array}{ccc}y=2x-6\\y=-x-3\end{array}\right\\\\\text{These are linear functions. We only need two points to draw a graph.}\\\\\text{Choice two values of x, substitute to the equation,}\\\text{and calculate the values of y.}\\\\y=2x-6\\for\ x=0\to y=2(0)-6=0-6=-6\to(0,\ -6)\\for\ x=3\to y=2(3)-6=6-6=0\to(3,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=3-3=0\to(-3,\ 0)\\\\\text{Look at the picture}

\text{The intersection of the line is the solution of the system of equations:}\\\\(1,\ -4)\to x=1,\ y=-4

7 0
3 years ago
If the average weight of sophomore boys in Arizona is 140 pounds with a standard
yKpoI14uk [10]

Answer:

Light

Step-by-step explanation:

He is below the standard deviation limits for average or normal.

5 0
3 years ago
Find the value of x that make it true
lesantik [10]

Answer:

Step-by-step explanation:

1). 10 = \frac{1+7x}{7+x}

   10(7 + x) = 1 + 7x

   70 + 10x = 7x + 1

   10x - 7x = 1 - 70

   3x = -69

   x = -23

2). 0.2 = \frac{6+2x}{12+x}

    0.2(12 + x) = 6 + 2x

    2.4 + 0.2x = 6 + 2x

    2.4 - 6 = 2x - 0.2x

    1.8x = -3.6

    x = -2

3). 0.8 = \frac{x}{x+0.5}

    0.8(x + 0.5) = x

    0.8x + 0.4 = x

    x - 0.8x = 0.4

    0.2x = 0.4

    x = 2

4). 3.5 = \frac{4+2x}{0.5-x}

    3.5(0.5 - x) = 4 + 2x

    1.75 - 3.5x = 4 + 2x

    -3.5x - 2x = 4 - 1.75

    -5.5x = 2.25

     x = -\frac{2.25}{5.5}

     x = - \frac{9}{22}

6 0
3 years ago
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