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andrew11 [14]
2 years ago
14

Lines A and B are parallelA1/23/125°B5/67/8m 6 = [ ?] ​

Mathematics
1 answer:
USPshnik [31]2 years ago
5 0
<h3>Answer:   55</h3>

==============================================

The 125 degree angle and angle 6 are supplementary. This is because of the same side interior angles theorem.

Let x be the measure of angle 6. Add this to 125, set the sum equal to 180, and solve for x.

x+125 = 180

x = 180-125

x = 55

------------

Or you could approach it this way:

y = measure of angle 2

y+125 = 180

y = 55

angle 6 = angle 2 (corresponding angles)

angle 6 = 55 degrees

-------------

Yet another way you could solve:

z = measure of angle 3

z+125 = 180

z = 55

angle 6 = angle 3 (alternate interior angles)

angle 6 = 55 degrees

A similar approach using alternate interior angles would involve angle 5 = 125, and then noticing that x+125 = 180 solves to x = 55

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a basketball team played five games . in those games , the team won by 7 points , lost by 3 , won by 4, lost by 2 , and won by 9
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Step-by-step explanation:

7-3+4-2+9=15

15/5=3

6 0
3 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
Why do I need to pay to see answers....
Korvikt [17]
Same girl oh my god it won’t let me ask anymore questions. Not my fault my math teacher gave me 30 questions to ask
8 0
3 years ago
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A train is traveling at the rate of 135 miles per hour. How far will the train travel in 3 hours?
dedylja [7]

Answer:

d.405

Step-by-step explanation:

135 x3=405

4 0
2 years ago
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