Prove that the parallelogram circumscribing a circle is a rhombusMatch the
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Answer: 2t + -8
Step-by-step explanation: Let's simplify this problem using the distributive property.
The first thing we want to do is change this minus to plus a negative.
Now we can distribute or multiply this 2 times
each of the terms inside the set of parentheses.
So we get 2(t) + 2(-4) and this simplifies to 2t + -8.
2t + -8 is the same thing as 2t -8.
