Prove that the parallelogram circumscribing a circle is a rhombusMatch the
1 answer:
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Answer : B
the distance between the points (4,3) and (2,-1)
We apply distance formula
(x1,y1) is (4,3)
(x2,y2) is (2,1)
d^2 = 4+16 = 20
Take square root on both sides
So
the distance between the points (4,3) and (2,-1) is 2sqrt(5)
The value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.
<h3>What is a function?</h3>It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The question is incomplete.
The complete question is attached in the picture please refer to the picture.
We have a function:
Plug t = 1
After solving:
F(1) = 1/2
Thus, the value of the F(1) is 1/2 option (C) is correct after plugging the value of t = 1 in the provided function.
Learn more about the function here:
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