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MAVERICK [17]
3 years ago
13

Prove that the parallelogram circumscribing a circle is a rhombusMatch the​

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

oops,,,the dimensions aren't perfect for this

sorry

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60 + 7.20 + 7.80 please math is so dumb ​
Alja [10]
75
60+7.20= 67.20
67.20+7.80= 75
6 0
3 years ago
Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?​
Annette [7]

Answer:

AD = 13

Step-by-step explanation:

Area of trapezoid ABCD

=  \frac{1}{2} (AB + AD) \times AB \\  \\  525=  \frac{1}{2} (37+ AD) \times21\\  \\  525 \times 2=  (37+ AD) \times21 \\  \\ 1050 = 21 \times 37 + 21AD \\  \\ 1050  = 777+ 21AD \\  \\  21AD  = 1050 - 777 \\  \\ 21AD  = 273 \\  \\ AD  =  \frac{273}{21}  \\  \\ AD  = 13

8 0
3 years ago
Please help
Rudiy27
It would be C since a scale factor of 2 makes the original A coordinate of (3,3) times 2 therefore the new coordinates being (6,6)
5 0
3 years ago
Need helppp please!!!!!!
Zielflug [23.3K]

b is an ipotenuse, so b > a and 2a+b>3a

8 0
3 years ago
Which angle is an acute angle?
Aleks [24]

Answer:

<CPB

Step-by-step explanation:

Because <APE= right angle

<APC= Obtuse angle

<CPE= Obtuse Angle.

Also, <CPB because its the only angle below 90 degrees and an acute angle must be below 90 degrees.

8 0
1 year ago
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