3 years ago

Prove that the parallelogram circumscribing a circle is a rhombusMatch the

Mathematics

1 answer:

RUDIKE [14]3 years ago

5 0

Answer:

oops,,,the dimensions aren't perfect for this

sorry

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60 + 7.20 + 7.80 please math is so dumb

Alja [10]

75
60+7.20= 67.20
67.20+7.80= 75

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3 years ago

Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?

Annette [7]

Answer:

AD = 13

Step-by-step explanation:

Area of trapezoid ABCD

$= \frac{1}{2} (AB + AD) \times AB \\ \\ 525= \frac{1}{2} (37+ AD) \times21\\ \\ 525 \times 2= (37+ AD) \times21 \\ \\ 1050 = 21 \times 37 + 21AD \\ \\ 1050 = 777+ 21AD \\ \\ 21AD = 1050 - 777 \\ \\ 21AD = 273 \\ \\ AD = \frac{273}{21} \\ \\ AD = 13$

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3 years ago

Please help

Rudiy27

It would be C since a scale factor of 2 makes the original A coordinate of (3,3) times 2 therefore the new coordinates being (6,6)

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3 years ago

Need helppp please!!!!!!

Zielflug [23.3K]

b is an ipotenuse, so b > a and 2a+b>3a

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3 years ago

Which angle is an acute angle?

Aleks [24]

Answer:

<CPB

Step-by-step explanation:

Because <APE= right angle

<APC= Obtuse angle

<CPE= Obtuse Angle.

Also, <CPB because its the only angle below 90 degrees and an acute angle must be below 90 degrees.

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1 year ago

Prove that the parallelogram circumscribing a circle is a rhombusMatch the​

Prove that the parallelogram circumscribing a circle is a rhombusMatch the