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vichka [17]
2 years ago
6

The length of two sides of a right triangle are given. Find the length of the third side. Round to the nearest tenth if necessar

y let’s: 28 in and 15 in
Mathematics
2 answers:
taurus [48]2 years ago
8 0
Taking the 28 and 15 to be the lengths of two shorter sides, we can get the hypotenuse using the formula;

a²+b²=c², Where a and b are the base and height of the triangle and c is the hypotenuse. 
So, c²=a²+b²
      c²=28²+15²
      c²=784+225
      c²=1009
      c=√1009
        = 31.8
mezya [45]2 years ago
7 0
To solve this problem you must apply the proccedure shown below:

 You must apply the Pythagorean Theorem.

 a) Taking 28 inches as the hypotenuse of the right triangle (the largest side), you have:

 a^2=b^2+c^2

 Where "a" is the hypotenuse, and "b" and "c" are the other sides of the right triangle.

 Then, you have:

 a=28 inches
 b=15 inches

 c^2=a^2-b^2 
 c=√(a^2-b^2)
 c=23.6

 Therefore, the answer is: 23.6 inches

 
a) Taking 28 inches as a one the other sides that are smaller than the hypotenuse, you have:

 a=√(b^2+c^2)

 Where "a" is the hypotenuse

 a=31.8 inches

  The answer is: 31.8 inches
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\large\bf{\underline{Given :}}

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__________________________________________

\large\bf{\underline{To \:prove :}}

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__________________________________________

\large\bf{\underline{In \: triangle \: ABD\:and\: triangle\:ADC}}

{⟹AD = AD\:\:\:\:\:\:\:\:\:\:\:\:\:\:( common)}

{⟹∠BAD = ∠CAD\:\:\:\:\:\:\:\:\:( given : AD \:is \:bisector \:of \:∠A )}

{⟹∠ABD = ∠ACD\:\:\:\:\:\:\:\:\:( given : angles\: in \:isosceles\: trianlge )}

\large\bf{\underline{Hence}}

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\large\bf{\underline{So}}

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__________________________________________

\large\bf{\underline{Note :}}Slide to view full answer.

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