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vichka [17]
3 years ago
6

The length of two sides of a right triangle are given. Find the length of the third side. Round to the nearest tenth if necessar

y let’s: 28 in and 15 in
Mathematics
2 answers:
taurus [48]3 years ago
8 0
Taking the 28 and 15 to be the lengths of two shorter sides, we can get the hypotenuse using the formula;

a²+b²=c², Where a and b are the base and height of the triangle and c is the hypotenuse. 
So, c²=a²+b²
      c²=28²+15²
      c²=784+225
      c²=1009
      c=√1009
        = 31.8
mezya [45]3 years ago
7 0
To solve this problem you must apply the proccedure shown below:

 You must apply the Pythagorean Theorem.

 a) Taking 28 inches as the hypotenuse of the right triangle (the largest side), you have:

 a^2=b^2+c^2

 Where "a" is the hypotenuse, and "b" and "c" are the other sides of the right triangle.

 Then, you have:

 a=28 inches
 b=15 inches

 c^2=a^2-b^2 
 c=√(a^2-b^2)
 c=23.6

 Therefore, the answer is: 23.6 inches

 
a) Taking 28 inches as a one the other sides that are smaller than the hypotenuse, you have:

 a=√(b^2+c^2)

 Where "a" is the hypotenuse

 a=31.8 inches

  The answer is: 31.8 inches
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I thought it was 25/100 buts it’s wrong
viva [34]

Answer:

Step-by-step explanation:

a to b represents a quarter of the line segment in order to get to %100 we need to multiply 2in by 4.

2x4=8

4 0
3 years ago
Find (f*f)(x) for the function f(x)=8x+9 and simplify
Alexus [3.1K]

Answer:

f(fx) = 64x + 81

Step-by-step explanation:

f(x) = 8x + 9

f(fx) = 8(8x+9) + 9

= 64x + 72 + 9

= 64x + 81

(Correct me if i am wrong)

5 0
3 years ago
Read 2 more answers
Ajar contains 4 red marbles numbered 1 to 4 and 10 blue marbles numbered 1 to 10. A marble is
Reptile [31]

Answer:

a)2/7

b)1/2

c)9/14

d)6/7

Step-by-step explanation:

The jar contains 4 red marbles, numbered 1 to 4 which means

Red marbles = (R1) , (R2) , (R3) , (R4)

It also contains 10 blue marbles numbered 1 to 10 which means

Blue marbles = (B1) , (B2) , (B3) , (B4) , (B5) , (B6) , (B7) , (B8) , (B9) , (B10) .

We can calculate total marbles = 4red +10 blues

=14marbled

Therefore, total marbles= 14

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10) =7

Total number of Blue marbles = 10

Blue and even marbles = 5

(a) The marble is red

P(The marble is red)=total number of red marbles/Total number of marbles

=4/14

=2/7

(b) The marble is odd-numbered

Blue marbles with odd number= (B1) , (B3) , (B5) , (B7) , (B9) ,

Red marbles with odd number = (R1) , (R3)

Number of odd numbered =(5+2)=7

P(marble is odd-numbered )= Number of odd numbered/ Total number of marbles

P(marble is odd-numbered )=7/14

=1/2

(C) The marble is red or odd-numbered?

Total number of red marbles = 14

Number of red and odd marbles = 2

The marbles that has odd number = (R1) , (R3) ,(B1) , (B3) , (B5) , (B7) , (B9) =7

n(red or even )= n(red) + n(odd)- n(red and odd)

=4+7-2

=9

P(red or odd numbered)= (number of red or odd)/(total number of the marble)

= 9/14

(d) The marble is blue or even-numbered?

Number of Blue and even marbles = 5

Total number of Blue marbles = 10

Number of blue that are even= 5

The marbles that has even number = (R2) , (R4) ,(B2) , (B4) , (B6) , (B8) , (B10)

=7

n(Blue or even )= n(Blue) + n(even)- n(Blue and even)

= 10+7-5 =12

Now , the probability the marble is blue or even numbered can be calculated as

P(blue or even numbered)= (number of Blue or even)/(total number of the marble)

= 12/14

= 6/7

6 0
3 years ago
Find the probability of each event. A gambler places a bet on a horse race. To win, he must pick the top three finishers in any
Lina20 [59]

Answer: \dfrac{1}{56}

Step-by-step explanation:

Total horses = 6

Number of ways to choose top 3 finishers in order = 3! = 6

Number ways to select 3 horses out of 8 in order = ^8P_3  [By permutations]

=\dfrac{8!}{(8-3)!}=\dfrac{8!}{5!}=8\times7\times6=336

Now, the probability that the gambler will win his bet =

\dfrac{\text{Number of ways to choose top 3 finishers }}{\text{Number ways to select 3 horses out of 8 in order}}

=\dfrac{6}{336}\\\\=\dfrac{1}{56}

Hence, the required probability =  \dfrac{1}{56}

3 0
3 years ago
Josh volunteered at the zoo for 14 hours in one month. This was 3 1/2 times as many hours as Gina volunteered. How many hours di
jonny [76]
This one you can't really make a formula for or anything, but it's fairly simple to figure out, with a bit of guess and check.
14 is really close to 15, but that's bigger, so let's try a smaller number that would work.
It has to be divisible by 2, because you've got a whole number that is 3 1/2 times the other number. (1/2 of a whole number means it's divisible by 2).
10 is divisible by 2,
10 ÷ 2 = 5
But, 10 x 3 = 30 which is much bigger than 14.
So, we've got to start with a smaller number.
Let's try something really small, like 4. We could try 2, but 2 x 3 = 6, which, even with 1/2 of 2, isn't nearly close to 14.
Now, 4 x 3 = 12
That's quite close to 14.
And 1/2 of 4 is 2.
All we do now is add 12 to 2 and see if it works.
12 + 2 = 14
14 = 14
This one works.
That means that Gina volunteered for 4 hours, because 3 1/2 x 4 = 14.
5 0
3 years ago
Read 2 more answers
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