The length of two sides of a right triangle are given. Find the length of the third side. Round to the nearest tenth if necessar
y let’s: 28 in and 15 in
2 answers:
Taking the 28 and 15 to be the lengths of two shorter sides, we can get the hypotenuse using the formula;
a²+b²=c², Where a and b are the base and height of the triangle and c is the hypotenuse.
So, c²=a²+b²
c²=28²+15²
c²=784+225
c²=1009
c=√1009
= 31.8
To solve this problem you must apply the proccedure shown below:
You must apply the Pythagorean Theorem.
a) Taking 28 inches as the hypotenuse of the right triangle (the largest side), you have:
a^2=b^2+c^2
Where "a" is the hypotenuse, and "b" and "c" are the other sides of the right triangle.
Then, you have:
a=28 inches
b=15 inches
c^2=a^2-b^2
c=√(a^2-b^2)
c=23.6
Therefore, the answer is: 23.6 inches
a) Taking 28 inches as a one the other sides that are smaller than the hypotenuse, you have:
a=√(b^2+c^2)
Where "a" is the hypotenuse
a=31.8 inches
The answer is: 31.8 inches
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Step-by-step explanation:
Given equations are
x - 2y - z = 2
x + 3y - 2z = 4
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from the given equations the augmented matrix can be written as
![\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-1%3A2%5C%5C1%263%26-2%3A4%5C%5C-1%262%263%3A2%5Cend%7Barray%7D%5Cright%5D)
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![=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-2%26-1%3A2%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)
![=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26-1-%5Cdfrac%7B2%7D%7B5%7D%3A2%2B%5Cdfrac%7B4%7D%7B5%7D%5C%5C%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)
![=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]](https://tex.z-dn.net/?f=%3D%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%26%5Cdfrac%7B-7%7D%7B5%7D%3A%5Cdfrac%7B14%7D%7B5%7D%5C%5C%5C%5C0%261%26%5Cdfrac%7B-1%7D%7B5%7D%3A%5Cdfrac%7B2%7D%7B5%7D%5C%5C%5C%5C0%260%262%3A4%5Cend%7Barray%7D%5Cright%5D)
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So, from the above augmented matrix, we can write
z = 2
72 inches cubed is the answer
A simplified ratio may always be a rate.
Answer:
Step-by-step explanation:
Add 5 to both sides
x = 6
Add 3 to both sides
x = -15 +3
x = -12
