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professor190 [17]
3 years ago
9

Help me please........

Mathematics
1 answer:
arlik [135]3 years ago
6 0

AC=AC (reason: reflexive property)

Step-by-step explanation:

Hope it helps you!

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Tia and Ken each sold snack bars and magazines for a fundraiser. Tia sold 16 snack bars
Natalija [7]

Answer:

64

Step-by-step explanation:

you have to multiply

6 0
3 years ago
I need the answers for this question.
nadya68 [22]

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7

Step-by-step explanation:

7 0
3 years ago
Fractions order from least to greatest<br> Which is the right answer? Pls help ill give brainliest!!
olya-2409 [2.1K]

Answer:

2/5, 4/7, 5/2

Step-by-step explanation:

5/2=2.5     2/5=.40    4/7= .59 that's aproximately  for 4/7

8 0
3 years ago
Solve system of equations 2x + 2y + 5z = 7 6x + 8y + 5z = 9 2x + 3y + 5z = 6
svet-max [94.6K]

Answer:

the values of x, y and z are x= 2, y =-1 and z=1

Step-by-step explanation:

We need to solve the following system of equations.

We will use elimination method to solve these equations and find the values of x, y and z.

2x + 2y + 5z = 7     eq(1)

6x + 8y + 5z = 9     eq(2)

2x + 3y + 5z = 6     eq(3)

Subtracting eq(1) and eq(3)

2x + 2y + 5z = 7

2x + 3y + 5z = 6

-    -       -        -

_____________

0 -y + 0 = 1

-y = 1

=> y = -1

Subtracting eq(2) and eq(3)

6x + 8y + 5z = 9    

2x + 3y + 5z = 6    

-     -      -          -

______________

4x + 5y +0z = 3    

4x + 5y = 3      eq(4)

Putting value of y = -1 in equation 4

4x + 5y = 3

4x + 5(-1) = 3

4x -5 = 3

4x = 3+5

4x = 8

x= 8/4

x = 2

Putting value of x=2 and y=-1 in eq(1)

2x + 2y + 5z = 7

2(2) + 2(-1) + 5z = 7

4 -2 + 5z = 7

2 + 5z = 7

5z = 7 -2

5z = 5

z = 5/5

z = 1

So, the values of x, y and z are x= 2, y =-1 and z=1

5 0
4 years ago
The graph of which function has an axis of symmetry at x=3?​
iragen [17]

Answer:

A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12

Step-by-step explanation:

In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.

x = -b/2a

In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.

3 = -b/2(1)

3 = -b/2

6 = -b

b = -6

Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.

5 0
4 years ago
Read 2 more answers
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