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andrey2020 [161]
3 years ago
12

Grace and her brother need $400 to go to band camp. Their parents have agreed to help them earn money by paying them $25 each ti

me they mow the lawn and $10 for each hour they babysit their younger brother. They will have to do a combination of both chores to earn the money.
Select the equation that represents the number of lawns they can mow, m, and hours they can babysit, b, to earn $400.
M. 10m+ 25b= 400
P. 10m− 25b= 400
R. 25m+ 10b= 400
S. 25m− 10b= 400
Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer:

25m + 10b = 400

Step-by-step explanation:

Total amount that can be earned = $ 400

Amount earned on mowing a lawn = $ 25

Amount earned per hour on babysitting = $10

Amount earned for mowing one lawn is $ 25, so amount earned for mowing m lawns will be $ 25m

Amount earned for one hour of babysitting is $ 10, so amount earned for babysitting for b hours will be $ 10b

Total amount earned = Amount earned from mowing m lawns + Amount earned from babysitting for b hours

Using the values from above, we can set up the equation as:

400 = 25m + 10b

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4r - 10s? can someone please help me with my math homeowrk?
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Answer:

4r - 10s OR 4r + (-10s)

Step-by-step explanation:

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2 years ago
Cushing's disease is characterized by muscular weakness due to adrenal or pituitary dysfunction. To provide effective treatment,
Katyanochek1 [597]

Answer:

Since the calculated value of t =-0.427 does not  fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

Step-by-step explanation:

The given data is

Difference d= -24 -12 -55 -15 -30 -60 -14 -21 -48 -12 -25 -53 -61 -69 -80

∑ d= -579

 ∑d²= 29871

1) Let the hypotheses be

H0: ud= 25 against the claim    Ha: ud ≠25

H0 : mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

Ha:   mean difference in the  age of onset of symptoms and age of diagnosis is not 25 months.

 

2) The degrees of freedom = n-1= 15-1= 14

3) The significance level is 0.05

4) The test statistic is

t= d`/sd/√n

The critical region is ║t║≤ t (0.025,14) = ±2.145

d`= ∑di/n= -579/15= -38.6

Sd= 23.178  (using calculators)

Therefore

t= d`/ sd/√n

t= -38.6/ 23.178√15

t= -1.655/3.872= -0.427

5) Since the calculated value of t =-0.427 does not  fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

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3 years ago
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80 because tens place is two over from the right

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