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dangina [55]
3 years ago
7

The width of rectangle A is the sum of twice a number and 8. The length of the rectangle is 3 times as great as the width. If th

e perimeter is 96, find the length and the width.
Mathematics
1 answer:
Igoryamba3 years ago
8 0

width = 2n+8

length = 3 * width = 3*(2n+8) = 6n+24

Perimeter = 2(l+w)

                  = 2(  6n+24 + 2n+8)

                  = 2( 8n+32)

           96   = 16n +64

          -64            -64

--------------------------------------

        32  = 16n                              divide by `16

        2 = n

width = 2n+8 = 2*n + 8=  4 + 8 = 12

length = 3*width = 3*12 = 36

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Answer:

Width = y + 7x

Step-by-step explanation:

Area of the rectangle = {y}^{2}  + 8xy + 7 {x}^{2}

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Lets factorise {y}^{2}  + 8xy + 7 {x}^{2}

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Now ,

Width = \frac{Area}{Length}  =  \frac{(y + 7x)(y + x)}{(y + x)}  = y + 7x

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