Answer: data loss protection
Explanation:
In any organization or enterprise it is very essential to provide protection from data loss to avoid breaches by unauthorized accesses and to secure the data irrespective of whether it is in rest or motion.
It is known that data changes its form when it is copied, moved and stored in different memory location so in this process a lot of sensitive data might be exposed to the outside world and left into the hands of the unauthorized for easy of access to it.
So once a security breach is possible through the system or into the network of the organization it would expose all the application database, emails, spreadsheets and the personal workstation files. So in such a scenario the importance of data loss protection is highlighted and must be given due importance.
Answer:
The flashdrive can hold 35389 400-pages-books
Explanation:
If 
of a page occupies 1 kB of memory, we can calculate how much memory a book will take
Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.
To do the calculation, we have to know how many kilobytes are in 9 gigabytes.
There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:
Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.
The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.
Answer:
Customer Table
- Customer name
- Customer id
Product Table
- Product id/number (primary key, auto increment)
- Product name
- Product sale price
Transactions Table
- Transaction Id
- Customer Id
- Product id
- Quantity
- Price
- Date
Explanation:
Natalie wants to fetch following information from database
- Look up customer name and sale price
- Sort items in db by product number
To lookup customer name and sale price perform a join on Transactions table and Customer table.Assuming database is build in mysql the query to fetch required results would be
select transction.productId,transaction.customerid,customer.customername from transactions join customer ON
customer.customerid=transcation.customerid
where productid="user provided product id of returned product"
For sorting products by number set produc number in product table a auto increment primary key
