Answer:
60
Step-by-step explanation:
Pythagorean Theorem; a² + b² = c²
a = 11
b = ?
c = 61
You can solve to get 60
Yes you got the problem right
Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
