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dezoksy [38]
3 years ago
15

This box plot shows the weights, in ounces, of some kittens.

Mathematics
2 answers:
choli [55]3 years ago
6 0
D which is 7.5 is the interquartile range of the weights, in ounces, of the kittens
umka21 [38]3 years ago
3 0

Answer:

2.5

Step-by-step explanation:

hope it helps :)

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Solve the equation for x. 4^5 square root (2x-4)^2=16
VMariaS [17]

The value of x in the equation is 4

<h3>What are algebraic expressions?</h3>

Algebraic expressions are seen as expressions that consist of factors, variables, terms, coefficients, and certain constants.

These expressions are also known to be composed of some arithmetic operations, which includes;

  • Subtraction
  • Addition
  • Division
  • Multiplication
  • Parentheses
  • Bracket, etc

Given the expression;

(2x-4)^2=16

√(2x-4)^2 = 16

Find the square root of the expression, we have;

√(2x -4)^2= √16

Find the values

2x - 4 = 4

collect like terms

2x = 4 + 4

Add like terms

2x = 8

Make 'x' the subject of formula

x = 8/2

x = 4

Hence, the value is 4

Learn more about algebraic expressions here:

brainly.com/question/4344214

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6 0
2 years ago
What would be the answer to this question?<br> -31=26+a
shtirl [24]

Answer:

a=-57

Step-by-step explanation:

-31=26+a

-26-31=a

a=-57

5 0
4 years ago
Read 2 more answers
Solve the triangle. Round your answers to the nearest tenth.
mixas84 [53]

Answer:

Angles: \angle A = 43^{\circ}   \angle B = 55^{\circ}    \angle C = 82^{\circ}

Sides: BC = 20   AB = 29   AC =24

Step-by-step explanation:

See attachment for complete question

From the attachment, we have:

AB = 29

AC =24

\angle C = 82^{\circ}

Required

Complete the missing side and missing angles

To calculate angle B, we apply sine laws:

\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}

In this case:

\frac{AB}{sinC}=\frac{AC}{sinB}

This gives:

\frac{29}{sin(82^{\circ})}=\frac{24}{sinB}

\frac{29}{0.9903}=\frac{24}{sinB}

Cross Multiply

sinB * 29 = 24 * 0.9903

Divide both sides by 29

sinB  = \frac{24 * 0.9903}{29}

sinB  = 0.8196

Take arcsin of both sides

B  = sin^{-1}(0.8196)

B = 55^{\circ}

So:

\angle B = 55^{\circ}

To solve for the third angle, we make use of:

\angle A + \angle B + \angle C = 180^{\circ}

This gives:

\angle A + 55^{\circ} + 82^{\circ} = 180^{\circ}

\angle A + 137^{\circ}= 180^{\circ}

\angle A = 180^{\circ}- 137^{\circ}

\angle A = 43^{\circ}

Hence, the angles are:

\angle A = 43^{\circ}   \angle B = 55^{\circ}    \angle C = 82^{\circ}

To calculate the length of the third side, we apply cosine law

BC^2 = AB^2 + AC^2 - 2*AB*AC*cosA

BC^2 = 29^2 + 24^2 - 2*29*24*cos(43^{\circ})

BC^2 = 841+ 576 - 1392*cos(43^{\circ})

BC^2 = 841+ 576 - 1392*0.7314

BC^2 = 841+ 576 - 1018.11

BC^2 = 398.89

Take the square root of both sides

BC = \sqrt{398.89

BC = 19.9722307217

BC = 20

5 0
3 years ago
Triangle: 3x-1,4x+1,3x<br> perimeter:70cm<br> area:A2<br> find A
Pepsi [2]

Answer:

A = 210 cm²

Step-by-step explanation:

Perimeter of the triangle = the sum of the sides of the triangle.

70 = (3x - 1) + (4x + 1) + (3x)

70 = 10x  

7 = x     The length of the sides of the triangle are 3x - 1 = 20;  4x + 1 = 29 and                

             3x = 21.

 Looking at the given information, this triangle is a special type of triangle because the area of a triangle is Area = 1/2 bh and you do not know which side is the base and height of the triangle.

Trying a² + b² = c² to see if it is a right triangle.   20² + 21² = 29 ² ; yes it is a right triangle and now we know that the base and height is 20 and 21.   The longest side is the hypotenuse in a right triangle

A = 1/2bh

A = 1/2 (20)(21)

A = 10 · 21

A = 210 cm²

6 0
3 years ago
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Ludmilka [50]
1 is company k and 2 is company is j
6 0
3 years ago
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