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3 years ago

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What is the equation of the line that is parallel to the given line and passes through the point (2, 3)?

2 answers:

Lelechka [254]3 years ago

3 0

Answer:

(-4,0)(4,-4)

slope(m) = (-4 - 0) / (4 - (-4) = -4/(4 + 4) = -4/8 = -1/2. A parallel line will have the same slope.

y = mx + b

slope(m) = -1/2

(2,3)...x = 2 and y = 3

now we sub and find b, the y int

3 = -1/2(2) + b

3 = -1 + b

3 + 1 = b

4 = b

y = -1/2x + 4

1/2x + y = 4....multiply by 2

x + 2y = 8 <== ur parallel line

mr_godi [17]3 years ago

3 0

Answer:

D: 2x + y = 8

Step-by-step explanation:

on edge2021! hope this helps!!~ （=´∇｀=）

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Find the area under the standard normal probability distribution between the following pairs of z-scores. a. z=0 and z=3.00 e.

prohojiy [21]

Answer:

a. P(0 < z < 3.00) = 0.4987

b. P(0 < z < 1.00) = 0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) = 0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) = 0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d. z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5 and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014 and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587 and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 - 0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571 and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 - 0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148 and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 - 0.2148

P(-0.79 < z < 0) = 0.2852

8 0

3 years ago

An observer for a radar station is located at the origin of a coordinate system. Find the bearing of an airplane located at the

AfilCa [17]

Answer:

135 degrees

$S45^{0}E$

Step-by-step explanation

Consider the attached diagram

we are required to find the bearing of the aeroplane,

Consider the right angled triangle BOE

|OB|=4 unit

|AB|=4 Units

$Tan \alpha =\frac{Opposite}{Adjacent} =\frac{4}{4} \\\\\alpha=Tan^{-1} 1=45 degrees$

The Bearing of the Aeroplane is therefore given:

(i)From North Clockwise as: 90+45 =135 degrees

(ii)From a North South Line as $S45^{0}E$

6 0

3 years ago

The park and movie theater are 3.4 inches apart on a map. If the map has a scale of 0.25 inch = 5 miles, find the actual distanc

lianna [129]

The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

Step-by-step explanation:

The given is,

Park and movie theater are 3.4 inches apart

Map has a scale of 0.25 inch = 5 miles

Step:1

Formula to calculate the number of scales for distance between park and theater,

$= \frac{Distance in map}{Scale value of map}$

$= \frac{3.4}{0.25}$

= 13.6

number of scales for distance between park and theater = 13.6

Step:2

Formula to convert distance inches to miles

$= Number of scale$ × $Equivalent value inches to miles$

= 13.6 × 5

= 68

Actual distance between park and theater = 68 miles

Result:

The actual distance between park and movie theater is 68 miles, if the park and movie theater are 3.4 inches apart on a map and the map has a scale of 0.25 inch = 5 miles.

6 0

3 years ago

See attachment for help.

Tema [17]

the correct answer is B.

7 0

3 years ago

Last one I promise!<br> Question is in the picture again

lawyer [7]

Answer:

C.

Step-by-step explanation:

C.

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2 years ago