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Brrunno [24]
3 years ago
13

Find SX if SM=6x-3 and XM=4x-8

Mathematics
2 answers:
Natali [406]3 years ago
8 0

Answer:

10x -11

Step-by-step explanation:

SX =SM + MX

       = 6x-3 + 4x-8

      Combine like terms

        = 10x -11

Monica [59]3 years ago
3 0
I believe that it is 6(4x-8) - 3
Which is 24x - 45.
Not sure but does this work?
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If the area of the rectangle is(xA^3−4x^2−15x+21) and the width is (x-6), what is the length?
pantera1 [17]

Answer:

hmm, imma have to do the problem

Step-by-step explanation:

7 0
3 years ago
What is the correct answer for this 5+1*10=
Viefleur [7K]
It would equal 15. To get 15, you would first do 1*10= which equals 10. After that, you would add 5 to the 10 then there's your answer. I hoped this helped!
8 0
3 years ago
Read 2 more answers
Can you help me plzs
Jlenok [28]

Answer:

164

Step-by-step explanation:

2x+7+5x+12=180

7x+19=180

7x+180-19

7x=171

----  ----

7      7

x=164

6 0
3 years ago
Read 2 more answers
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.
5 0
3 years ago
Read 2 more answers
What is the answer please
Likurg_2 [28]

Answer:

rhombus = a quadrilateral with four congruent sides

rectangle = a quadrilateral with four right angles

parallelogram = a quadrilateral with two pairs of parallel sides

trapezoid = a quadrilateral with one set of parallel sides

square = a quadrilateral with four right angles and four congruent sides

3 0
3 years ago
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