The answer is 62/25.
Hope this helps.
Answer:
Option 4
The answer is 10.8
Step-by-step explanation:
5/6 = 9/c
5c = 9 × 6
5c = 54
5c/5 = 54/5
c = 10.8
Thus, The value of c is 10.8
<h3>
<u>For </u><u>Verification</u>;</h3>
5/6 = 9/c
5/6 = 9/10.8
0.833 = 0.833
Hence, L.H.S = R.H.S
<u>-TheUnknownScientist</u><u> 72</u>
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719