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I am Lyosha [343]
3 years ago
9

Pls answer number 6 fast pls someone help

Mathematics
2 answers:
attashe74 [19]3 years ago
8 0

Answer:

It's in Quadrant IV.

..............

pentagon [3]3 years ago
8 0
Answer: D

Quadrant 4/lV
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2 numbers are in the ratio 1:2 if the first number is decreased by 5 and second number is increased by 4 their ratio becomes 5:4
Anna35 [415]

Answer:

-20/3 & -40/3

Step-by-step explanation:

Let’s say that the 1st number is X and the 2nd number is Y.

Given that x:y = 1:2 => x/y = 1/2 => 2x = y

and a-5/y+4 = 5/4 (The first number is decreased by 5 and the second number is increased by 4.)

=> 4(x - 5) = 5 (y + 4)

=> 4x - 20 = 5y + 20

=> 4x - 5y = 40

As, 2x = y , 4x = 2y

=> 2y - 5y = 40

=> -3y = 40

=> y = -40/3 ; x = y/2 = -20/3

This might be confusing but I hope this helps :)

7 0
3 years ago
Which answer !!!!!!!!!
ycow [4]
The first answer, answer A. It's easy.

3 0
3 years ago
In training to run a half marathon, Jenny ran 2/5 hours on Tuesday, 11/6 hours on
maria [59]

Answer:

Total hours that Jenny ran = 3.63 hours.

Step-by-step explanation:

Jenny ran on Tuesday for = 2/5 hours or 0.4 hours.

Time consumed to run on Thursday = 11/6 hours or 1.83 hours.

Time consumed to run on Saturday = 21/ 15 hours or 1.4 hours.

Here, the total hours can be calculated by just adding all the running hours. So the running hours of Tuesday, Thursday, and Saturday will be added to find the total hours.

Total hours that Jenny ran = 0.4 + 1.83 + 1.4 = 3.63 hours.

6 0
3 years ago
What is 4 1/2 + -17 1/4 it doesn’t have to be simplify xo
mestny [16]

Answer:

-14 3/4

Step-by-step explanation:

i am not super sure about this. the fraction is right though. i hope

5 0
2 years ago
(b)<br> 2sin(theta) + 1/sin(theta) - 1<br> = 0 for 0 &lt;_ x &lt; 2x
Lady bird [3.3K]

Answer:

2 - 2 cos²x = sin x

2 = sin x + 2 cos² x

0 = -2 + sin x + 2(1 - sin² x)

0 = -2 sin² x + sin x + 2 - 2

0 = 2 sin² x - sin x 0 = sin x (2 sin x - 1)

sin x = 0 v sin x = 0.5

x10° + k.360° x1 = 0°, 360°

x2 = (180° - 0°) + k.360°

x2 = 180°

x3 = 30° + k.360°

x3 = 30°

x4 = (180° -30°) + k.360° x4 = 150°

HP: {x | 0°, 30°, 150°, 180°, 360°)

8 0
2 years ago
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