Answer:
$30 per day
Step-by-step explanation:
2,100 divided by 70 is 30
The perimeter of a square is equal to the side length times 4.
The equation is P = 4S, with P being the perimeter, and S being a side.
Also, to get the length of a side from the perimeter, just divide the perimeter by 4.
To have it in centimeters, just add cm to the end of your answer!
So out of the amount in your account you have $10,000.
You get charged a 10% fee if you withdraw before you are 59.5 (you did, you were 48).
So, they are going to charge a 10% fee of the $2,500.
10% of $2,500 is...
Your Answer:
$250
Answer:
Step-by-step explanation:
The diagonals of a parallelogram bisect each other.
5y - 8 = 3y + 1 Add 8 to both sides
5y = 3y + 1 + 8 Subtract 3y from both sides
5y - 3y = 9 Combine
2y = 9 Divide by 2
2y/2 =9/2
y = 4. 5
5y - 8 =
5(4.5) - 8 =
22.5 - 8 =
14.5
That represents 1/2 of MO
MO = 2 * 14.5
MO = 29
bearing in mind that "a" is the length of the traverse axis, and "c" is the distance from the center to either foci.
we know the center is at (0,0), we know there's a vertex at (-48,0), from the origin to -48, that's 48 units flat, meaning, the hyperbola is a horizontal one running over the x-axis whose a = 48.
we also know there's a focus point at (50,0), that's 50 units from the center, namely c = 50.
![\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ \textit{asymptotes}\quad y= k\pm \cfrac{b}{a}(x- h) \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%5C%5C%20%5Ctextit%7Basymptotes%7D%5Cquad%20y%3D%20k%5Cpm%20%5Ccfrac%7Bb%7D%7Ba%7D%28x-%20h%29%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
