From calculus, to determine the maxima or minima of the graph, get the derivative of the equation and equate to zero. So, we derive first the equation of the graph and equate to zero.
C = 0.25x² - 80x + 30000
dC/dx = 0 = 0.5x - 80 + 0
0.5x = 80
x = 80/0.5
x = 160 units
The minimum cost (although not asked) is:
C = 0.25(160)² - 80(160) + 30000
C = $23,600
The answer is 160 units.
Answer:
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Step-by-step explanation:
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10.0.0.0/8 is variably subnetted, 3 subnets, 2 masksC10.1.1.0/30 is directly connected, Serial0/0/0L10.1.1.1/32 is directly connected, Serial0/0/0R10.2.2.0/30 [120/1] via 10.1.1.2, 00:00:21, Serial0/0/0172.30.0.0/16 is variably subnetted, 2 subnets, 2 masksC172.30.10.0/24 is directly connected, GigabitEthernet0/1L172.30.10.1/32 is directly connected, GigabitEthernet0/1R3 only displays its own subnets for the 172.30.0.0 network. R3 does not have any routes for the172.30.0.0 subnets on R1.
384,000 ounces turn into 12 tons
If you add two negative numbers you get a sum that is less than both of the numbers. so -1+-2=-3
