Answer:
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. (In grammar school, you probably called the domain the replacement set and the range the solution set. further the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
I hope it will help =)
Answer:
A
The first option is the correct!
They are parallel so they never connect! :)
Photos attached!
Hope this helps! Have a great day! :)
Answer:
+140.68 m/h
Step-by-step explanation:
17.33 h
2438.1/17.33 = 140.68
+140.68 m/h
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<h3>
Answer: x^2-3x+36</h3>
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Explanation:
The larger rectangle has area of (x+1)(x+1) = x^2+2x+1 through the use of the FOIL rule or distribution
If you use distribution, then it might help to let y = x+1 so we'd have y(x+1) lead to xy+1y which becomes x(x+1)+1(x+1). From there it might be easier to see how to get x^2+2x+1 after everything distributes again and simplifies.
The smaller rectangle has area 5x-35 which is found by distributing 5(x-7)
To get the shaded area, we subtract the two rectangle areas found above
shaded area = (larger area) - (smaller area)
shaded area = (x^2+2x+1) - (5x - 35)
shaded area = x^2+2x+1 - 5x + 35
shaded area = x^2-3x+36
Answer:
A= 0,2
B= 0,2
C= 0,4
D=0,2
Step-by-step explanation:
We know that only one team can win, so the sum of each probability of wining is one
P(A)+P(B)+P(C)+P(D)=1
then we Know that the probability of Team A and B are the same, so
P(A)=P(B)
And that the the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)
Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2
Now if we use the first formula:
P(A)+P(B)+P(C)+P(D)=1
P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1
0,5 P(A)+0.9=1
0,5 P(A)= 0,1
P(A)= 0,2
P(B)= 0,2
P(C)=0,4
P(D)=0,2
