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Lapatulllka [165]
3 years ago
13

I NEED HELP THIS IS DUE ASAP

Mathematics
2 answers:
Anettt [7]3 years ago
8 0
First two answers are : proportional, unproportional
UNO [17]3 years ago
6 0

Answer:

Proportional

Unproportional

Step-by-step explanation:

85 -6 = 79

79 -6 = 73

73 -6 = 67

1.49 +10 = 1.59

1.59 + 30 = 1.89

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Having trouble with this
GaryK [48]
Jayden ran 1/5 of his total distance in 1 minute. His total distance is 6/5 of a kilometer. He ran 6/25 of a kilometer in 1 minute or 3/5 of a lap.
7 0
3 years ago
Solve the equations.<br> a. (x − 2)^2 = 9<br> b. 3(x − 2)^2 = 9<br> c. 6 = 24(x + 1)^2
seropon [69]

Answer: a) x = 5 or -1 b) x = √3+2

c) x = -1/2 or -3/2

Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

x-2 = +-3

x = +3+2

x = 5 and;

x = -3+2

x = -1

x = 5 or -1

b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

√(x-2)² = √3

x-2 = √3

x = √3+2

c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

x = -1/2 or -3/2

4 0
3 years ago
Find the length of UC on the attached diagram. Thank you!
ValentinkaMS [17]
<h2>Answer </h2>

The length of UC is 18

<h2>Explanation </h2>

First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.

We can infer from our picture that JN is 82 + 105, so JN = 187

We can also infer that JU = JH + HU

                                     JU = 22 + 96

                                     JU = 118

We can also infer that CN = 51

Now we can fin the length of UC:

UC=JN-(JU+CN)

UC=187-(118+51)

UC=18

We can conclude that the length of UC is 18.

3 0
3 years ago
Read 2 more answers
Vertical Lines
noname [10]

Answer:

kk

Step-by-step explanation:

8 0
2 years ago
Can you please explain this?​
Leni [432]

Answer:

The question is giving you pairs of points in space which can be used to define lines. It is then asking you to determine if the lines defined by those points are parallel, perpendicular, or neither.

Step-by-step explanation:

Two key things you need to know to solve this is that the lines will be parallel if their slopes are the same, and perpendicular if one slope is the negative reciprocal of the other (i.e. s_{1} = -s_{2}^{-1})

Let's start with question 11. You are given two pairs of points, each of which describes a distinct line:

(3,5)-(1,1) and (0, 2)-(5, 12)

To find the slope of each pair, take the vertex with the lesser x co-ordinate, and subtract it from the vertex with the greater x co-ordinate.  That will give us a valid Δx and Δy to get the slope.

In the first pair, 3 > 1, so we'll subtract the second point from the first:

s = \Delta y / \Delta x\\s = \frac{5 - 1}{3 - 1}\\s = 4/2\\s = 2

So the first pair of vectors describe a line with a slope of 2.  Let's look at the other pair:

s = \Delta y / \Delta x\\s = (12 - 2) / (5 - 0)\\s = 10 / 5\\s = 2

That also gives us a slope of 2, meaning that the two lines are parallel.

This same process will need to be done for the other three questions.  We can't answer questions 12 or 14 here, as the last point is cut off on the edge of the image.  For question 3 though, one line has a slope of 7/3, and the other 3/7. That puts them in the "neither" category, as one is not the negative reciprocal of the other, but instead the positive reciprocal.

6 0
3 years ago
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