This should be recognized as the difference of perfect squares which is of the form:
(a^2-b^2) and the difference of squares always factors to:
(a-b)(a+b) in this case:
(3x-8)(3x+8)
-2x + 5 < 7
-2x + 5 < 7
<u> -5 -5 </u> deduct 5 from both sides
-2x < 2
<u>÷ -2 ÷ -2 </u> divide both sides by negative 2. Because of the division
x > -1 using a negative number, the sign is then reversed.
from < it becomes >.
The value of x should be greater than -1. It can be 0, 1, 2, so on...
To check: Revert back to the original sign which is <.
x = 1
-2x + 5 < 7
-2(1) + 5 < 7
-2 + 5 < 7
3 < 7
Answer:
a)6
b)v^2-u^2/2a
Step-by-step explanation:
a)Given that,
u=12
a= -6
s=9
We know that,
v^2=u^2+2as
or, v^2=(12)^2+2×(-6)×9
or,v^2=144-108
or,v^2=36
or, v=√36
∴v=6
(Ans)
b)If ,v^2=u^2+2as
then, u^2+2as=v^2
or,2as=v^2-u^2
or, s=v^2-u^2/2a
∴s=v^2-u^2/2a
Hope ya find it helpful.. Thanks a lot...
<span>X^3+6x^2-17x+2-x^3-x^2-11x+36 = </span>5x^2 - 28x + 38
Answer:
4.2846*10^2
Step-by-step explanation:
428.46
4.2846*10^2 hopefully
