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Sonja [21]
2 years ago
8

I NEED HELP PLEASE!!

Mathematics
1 answer:
Anna71 [15]2 years ago
7 0

Answer:

m = 2

Step-by-step explanation:

take 2 pairs from x

choose (1,5) and (2,7)

it will be m = 5 - 7

and in the bottom  1 - 2          it's a fraction

m = -2/-1

the numerator and denominator can't be both negative

so your answer is m= +2

m= slope

rate of change= slope

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coldgirl [10]
Changing the equation into slope form: y = mx + c, where m is the slope [gradient] and c is the y-intercept.

2x+3y=1470
3y = -2x+1470
y= - \frac{2}{3}x+ \frac{1470}{3}
y=- \frac{2}{3}x+490

The gradient is - \frac{2}{3} and y-intercept is at y=490

Graphing y=- \frac{2}{3}x+490 using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
    0 = - \frac{2}{3}x+490
    \frac{2}{3}x = 490
    2x = 1470
    x = \frac{1470}{2}
    x = 735
    So, x-intercept is at (735, 0)

The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735

-----------------------------------------------------------------------------------------------------------

Next month's profit equation

2x+3y=1593

Rewriting this into slope-equation form

3y = -2x+1593
y=- \frac{2}{3}+ \frac{1593}{3}
y= - \frac{2}{3}+531

The gradient, m, equals to - \frac{2}{3}
The y-intercept, c, equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept. 

-------------------------------------------------------------------------------------------------------------

A linear graph show points of (0, 300) and (450, 0)

We work out the slope: 
\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30}  =- \frac{2}{3}


Y-intercept at x = 0, so it's at y = 300

Equation y = - \frac{2}{3}+300

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NikAS [45]
216 muffins. it's 81*100 divided by 37.5
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