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3 years ago

Please answer I will mark branlest if you are right and I won't you all to be safe

Mathematics

1 answer:

erastova [34]3 years ago

3 0

Answer:

3. x=21

4. x=28

5. x=35

Step-by-step explanation:

I did ths step by step on my whiteboard and I know my answers are right. Sorry if that sounds cocky.

Can I get brainliest?

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It’s math can you guys help me out 10 points:)

qaws [65]

Answer:

90 liters

Step-by-step explanation:

please mark me as brainlest

8 0

2 years ago

Read 2 more answers

PLZZ HELPP YOU WILL BE THE BRAINLEIST!!!!!!!

sasho [114]

i need a graph so i can see then i will solve it

4 0

3 years ago

Read 2 more answers

Find the indicated real nth root(s) of a. n=3, a=729

marissa [1.9K]

Answer:

Step-by-step explanation:

n=3, a=729

For any odd integer, n ; a will have only one real nth root which will be a positive integer.

Similarly, for any integer, n, that is > 1 ; related by the expression ;

p^n = a ; the nth root of a = p

Therefore,

If n = 3 ; a = 729

p^3 = 729

To obtain the value of p ; take the cube of both sides

(p^3)*1/3 = 729^1/3

p = 9

Hence, the real nth root of 729 is +9 when n = 3

6 0

3 years ago

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago

Find the measure of each angle indicated. Round to the nearest tenth.

Sladkaya [172]

Answer:

Step-by-step explanation:

So we want to find θ. We are already given the hypotenuse and the side length opposite to θ. Therefore, we can use the trig function sine to find θ.

Recall that:

$\sin(\theta)=opp/hyp$

Plug in 10.2 for the opposite side and 15 for the hypotenuse:

$\sin(\theta)=10.2/15$

Solve for θ. Use a calculator:

$\theta=\sin^{-1}(10.2/15)\\\theta\approx42.8436\textdegree$

The answer is D.

5 0

3 years ago