Identify the graph containing the point (1,−5) .

Describe the graph of of the equation x = -2. Is the equation a function?

Cloud [144]

In the event that a line has no y-intercept, that implies it never converges the y-intercept, so it must be parallel to the y-intercept. This implies it is a vertical line, for example, . This slant of this line is vague. In the event that the line has no x-intercept, at that point it never meets the x-intercept, so it must be parallel to the x-pivot.

If x-intercept is -2 the line would be vertical as the y-intercept = 0.

7 0

3 years ago

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During an experiment, Aika measured the time it took for a ball to roll down a ramp set at an angle. She measured that it took 1

schepotkina [342]

Answer:

11.725%

Step-by-step explanation:

Given that :

True value = 0.904 seconds

Measured time = 1.010 seconds

Experimental error :

(|measured value - True value | / true value) * 100%

(|1.010 - 0.904| ÷ 0.904) * 100%

= 0.106 / 0.904 * 100%

= 0.1172566 * 100%

= 11.725%

4 0

3 years ago

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Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3>Let's understand the concept:-</h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3>Required Answer:-</h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

3 years ago

What is the equation of the line passing through the points (–25, 50) and (25, 50) in slope-intercept form?

allochka39001 [22]

The equation of the line passing through the points (-25, 50) and (25, 50) in slope-intercept form is y = 50. Hence, 4th option is the right choice.

The slope-intercept form of a line is written as y = mx + b, where m is the slope of the line, and b is the y-intercept.

The slope of a line passing through the points (x₁, y₁) and (x₂, y₂) can be calculated using the formula, slope (m) = (y₂ - y₁)/(x₂ - x₁).

Therefore, slope of the line passing through the points (-25, 50) and (25, 50) can be calculated as m = (50 - 50)/(25 - (-25)) = 0/(-50) = 0.

We can find the equation of the line using the point-slope formula, according to which, a line having a slope m and passing through the point (x₁, y₁) can be written as y - y₁ = m(x - x₁).

Therefore, the equation of the given line can be written as:

y - 50 = 0(x - 25)

or, y - 50 = 0,

or, y = 50.

Therefore, the equation of the line passing through the points (-25, 50) and (25, 50) in slope-intercept form is y = 50. Hence, 4th option is the right choice.

Learn more about the equation of a line at

brainly.com/question/18831322

#SPJ10

3 0

2 years ago

Y = -5x + 15 2x + y = 12

Nana76 [90]

Answer:

x = 1, y = 10

Step-by-step explanation:

y = -5x + 15 --- Equation 1

2x + y = 12 --- Equation 2

Substitute y = -5x + 15 into Equation 2:

2x + y = 12

2x - 5x + 15 = 12

Evaluate like terms.

15 - 3x = 12

Isolate -3x.

-3x = 12 - 15

Evaluate like terms.

-3x = -3

Find x.

x = -3 ÷ -3

x = 1

Substitute x = 1 into Equation 2:

2x + y = 12

2(1) + y = 12

2 + y = 12

Isolate y.

y = 12 - 2

y = 10

4 0

3 years ago

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