Identify the graph containing the point (1,−5) .

What is -3 2/3 x (-2 1/4)? A. -8 1/4. B. -6 1/6 C. 6 1/6. D. 8 1/4

juin [17]

Answer:

8 1/4

Step-by-step explanation:

Solution by Formulas

converting mixed numbers to fractions, our initial equation becomes,

−11 -9

3×4

Applying the fractions formula for multiplication,

−11×−9

3×4

=99

12

Simplifying 99/12, the answer is

=814

7 0

3 years ago

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What is bigger 3/10 or 3/8

olasank [31]

3/8 is bigger than 3/10. In maths 10ths are smaller than 8ths. If both have three parts it means that 3/8 must be bigger

7 0

3 years ago

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What is the value of x to the nearest degree?

Marrrta [24]

Answer:

Step-by-step explanation:

This is right triangle trig. The side opposite the x is 8, and the side adjacent to the x is 5. The tangent ratio uses those sides. We need to find what angle has a tangent of 8/5. To do this, make sure your calculator is in degree mode. Then hit "2nd" then tan and you will see tan with a little -1 and a parenthesis. Enter 8/5 and hit "enter" and you will get an angle measure of 57.9946. Rounded to the nearest degree this is 58 degrees. That's your answer!

8 0

3 years ago

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Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

Or

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

3 years ago

a group of 25 sixth graders, 40% of them said they had never visited another state. How many students said they had never visite

diamong [38]

Correct Answer: 10 students have never visited another state
40/100 × 25 =
40 is out of 100 because percentages always is represented by 100 (cent)

cross out the zero's equally top and bottom
so it would become: 4/100 × 25 = 4 ×25 = 100
then add the denominator
100/10 is our final resolution

cross out the zeros evenly and answer will give you 10.

6 0

3 years ago

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