All categories

3 years ago

Identify the graph containing the point (1,−5) .

Mathematics

1 answer:

harina [27]3 years ago

4 0

Answer:

we need a picture

Step-by-step explanation:

You might be interested in

The average american eats about 30 pounds of cheese per year. This is 3/5 the amount eaten my the average French person. How man

iragen [17]

What's 30-3/5???????

7 0

3 years ago

The table shows the price for shoe rental, games, and snacks at the bowling alley

monitta

First, find the total price she would have had to pay (without tax):
2.75+ 3(2.5)+ 1.75=12
If she has half-price multiply the total price by 0.5:
12(.5)=6
Her total price without tax is $6.

The answer is B) $6.00
Hope I helped...

6 0

4 years ago

a pair of sunglasses is on sale for $26. The original price of the sunglasses was $40. What percent of the original price is the

Xelga [282]

65%...
26 divided by 40 = 0.65 x 100 = 65%
hope this helps!

5 0

3 years ago

Read 2 more answers

What is the sum of -6 4/5 and 6 4/5

Damm [24]

Answer:

Step-by-step explanation:

same value negative plus positive is 0

8 0

3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago