Answer:
Step-by-step explanation:
Given:
U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}
A = {2,4,6,8,10,12,14}
B = {3,6,9,12,15}
C = {5,10,15}
(a) Verify A(BnB)=(AUB)(AUB)
A U (B n B)
= {2,4,6,8,10,12,14} U ( {3,6,9,12,15} n {3,6,9,12,15} )
= {2,4,6,8,10,12,14} U {3,6,9,12,15}
= {2,3,4,6,8,9,10,12,14,15}
( A U B) n (A U B)
= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}
= {2,3,4,6,8,9,10,12,14,15}
Therefore
A U (B n B) = ( A U B) n (A U B)
verifies
(b) Verify An(BUC)=(AnB)u(AnC)
A n ( B U C)
= {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )
= {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}
= {6,10,12}
( A n B ) U ( A n C )
= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )
= {6,12} U {10}
= {6,10,12}
Therefore
A n ( B U C) = ( A n B ) U ( A n C )
verifies
(c) Verify AU(BUC)=(AUB)U(AUC)
AU(BUC)
= {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}
= {2,3,4,5,6,8,9,10,12,14,15}
(AUB)U(AUC)
= ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})
= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}
= {2,3,4,5,6,8,9,10,12,14,15}
Therefore
AU(BUC)=(AUB)U(AUC)
verifies
