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3 years ago

3x+2y=-4I need help solving this. Pease help

Mathematics

1 answer:

marta [7]3 years ago

6 0

Steps to solve:
3x+2y=-4
3x=-4-2y
x=- \frac{4}{3}- \frac{2}{3}y [/tex]

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The perimeter of a rectangle is 46in and the diagonal is 17 in

dmitriy555 [2]

Answer + explaination

p=2*(L+l)=46

L+l=46:2

L+l=23

(L+l)^2=529

(L^2+l^2)+2l*L=529

D= V L^2+l^2= 17

L^2+l^2=289

so 289+2l*L=529

2l*L=529-289=240

l*L=240:2

A=120

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2 years ago

The Area of the net is 24 cm2. What is the side length of the cube?

Ymorist [56]

The side length of the cube is 6 cm.

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3 years ago

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Please I need help fast

Leya [2.2K]

Answer:

45 sq cm

Explanation:

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2 years ago

A taxi charges a flat rate of $1.75 plus an additional $0.65 per mile. If Erica has at most $10 to spend on the cab ride, how fa

tekilochka [14]

1.75 + 0.65m < = 10
0.65m < = 10 - 1.75
0.65m < = 8.25
m < = 8.25 / 0.65
m < = 12.69 miles <==

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3 years ago

The frequency distributions of two data sets are shown in the dot plots below.

fredd [130]

Answer:

1st, 4th and 6th statements are true.

Step-by-step explanation:

We have been given two dot-plots and we are asked to select all the true statements about given dot plots.

Let us write all the data points of both dot plots.

Data set 1:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 7.

Data set 2:

1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4.

1. The mean of data set 1 is greater than the mean of data set 2.

Let us find mean of both data sets.

$\text{Mean of data set 1}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}$

$\text{Mean of data set 1}=\frac{45}{19}$

$\text{Mean of data set 1}=2.3684\approx 2.37$

$\text{Mean of data set 2}=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}$

$\text{Mean of data set 2}=\frac{38}{18}$

$\text{Mean of data set 2}=2.11$

We can see that mean of data set 1 is greater than mean of data set 2, therefore, 1st statement is true.

2. The mean of data set 1 is equal to the mean of data set 2.

Since mean of data set 1 is greater than mean of data set 2, therefore, 2nd statement is false.

3. The median of data set 1 is greater than the median of data set 2.

Since data set 1 has 19 data points, so median of data set 1 will be value of 10th data set, that is 2.

Our data set 2 has 18 data points, so median of data set 2 will be the average of 9th and 10th data points.

$\text{Median of data set 2}=\frac{2+2}{2}$

$\text{Median of data set 2}=\frac{4}{2}=2$

Since median of data set 2 is also 2, therefore, 3rd statement is not true.

4. The median of data set 1 is equal to the median of data set 2.

Since both data set's median is 2, therefore, 4th statement is true.

5. The standard deviation of data set 1 is smaller than the standard deviation of data set 2.

Using online SD calculator we get SD of data set 1 is 1.422 and SD of data set 2 is 0.936. Since 1.422 is greater than 0.936, therefore, 5th statement is false.

6. The data sets have the same interquartile range.

$Q_1\text{ of data set 1}=1$

$Q_3\text{ of data set 1}=3$

$\text{IQR of data set 1}=3-1=2$

$Q_1\text{ of data set 2}=1$

$Q_3\text{ of data set 2}=3$

$\text{IQR of data set 2}=3-1=2$

Since both data set's IQR is 2, therefore, 6th statement is true.

3 0

3 years ago

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