Find the domain of the function 8x

What is the 50th term of the sequence that begins with -6, 0, 6, 12...

vazorg [7]

Answer:

The 50th term is 288.

Step-by-step explanation:

A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:

an = a1 + (n-1)*r

Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:

a50 = -6 + (50 - 1)*6

a50 = -6 + 49*6

a50 = -6 + 294

a50 = 288

The 50th term is 288.

5 0

4 years ago

An equation is shown below:

bekas [8.4K]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\texttt{Step 1: 18x − 42 = 2}$

$\texttt{Step 2: 18x = 44 }$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: 6(3x - 7) = 2$

Step 1 -

$\qquad \tt \rightarrow \: 18x - 42 = 2$

[ distributive property ]

Step 2 -

$\qquad \tt \rightarrow \: 18x = 2 + 42$

$\qquad \tt \rightarrow \: 18x = 44$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

2 years ago

PLEASE HELP ME

Kitty [74]

Answer:

C.

hope it help^_^(♡˙︶˙♡)

5 0

3 years ago

Which inequality is represented by this graph

sertanlavr [38]

The right answer is of option D.

 $x \geqslant 4$ 

In the given graph, X is greater than 4 and X equals to 4.

Hope it helps.....

Good luck on your assignment

4 0

4 years ago

The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb,

NNADVOKAT [17]

Answer:

bbbb,

bbbg, bbgb, bgbb, gbbb,

bbgg, bgbg, bggb, gbgb, gbbg, ggbb,

bggg, gbgg, ggbg, gggb,

gggg

Step-by-step explanation:

3 children: bbb, bbg, bgb, gbb, bgg, gbg, ggb, ggg

4 children: bbbb, bbbg, bbgb, bgbb, gbbb, bbgg, bgbg, bggb, gbgb, ggbb, bggg, gbgg, ggbg, gggb, gggg

You need to take a methodological approach;

The 2 easiest are the possibility of all boys and all girls;

Then consider 3 boys and 1 girl:

bbbg, bbgb, bgbb, gbbb

Then 2 boys and 2 girls:

bbgg, bgbg, bggb, gbgb, gbbg, ggbb

Lastly, 1 boy and 3 girls:

bggg, gbgg, ggbg, gggb

In total, there are 16 possibilities

P.S. interesting to note is that the number of possibilities here follows the pattern of Pascal's triangle:

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

The last row is relevant here;

There is 1 possibility where there are 4 boys;

There are 4 possibilities (in terms of the order of birth) where there are 3 boys and 1 girl;

There are 6 possibilities where there are 2 boys and 2 girls

There are 4 possibilities where there is 1 boy and 3 girls;

There is 1 possibility where there are 4 girls;

The pattern ∴ is 1 4 6 4 1, as the 5th row of Pascal's triangle reads;

If your talking about 3 children, it would match the 4th row of Pascal's triangle;

So, 1 possibility of 3 boys;

3 possibilities of 2 boys and 1 girl;

3 possibilities of 1 boy and 2 girls;

And 1 possibility of 3 girls;

If your talking about 10 children, it would match the 11th row of Pascal's triangle.

(Maths can be so cool XD)

7 0

3 years ago

Find the domain of the function 8x - 2y=8