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Nikitich [7]
3 years ago
7

What is the 50th term of the sequence that begins with -6, 0, 6, 12...

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

The 50th term is 288.

Step-by-step explanation:

A sequence that each term is related with the prior by a sum of a constant ratio is called a arithmetic progression, the sequence in this problem is one of those. In order to calculate the nth term of a setence like that we need to use the following formula:

an = a1 + (n-1)*r

Where an is the nth term, a1 is the first term, n is the position of the term in the sequence and r is the ratio between the numbers. In this case:

a50 = -6 + (50 - 1)*6

a50 = -6 + 49*6

a50 = -6 + 294

a50 = 288

The 50th term is 288.

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___________ is a standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph.
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Answer:

Unit of measure

Step-by-step explanation:

Unit of measure

When we construct any type of graph the unit of measure needs to be present, becuase the numbers without units are just numbers and with just the numbers we can't have physical interpretation of the situation.

For this reason is importatn to include the units of meausre with the plots since with that we have a point of reference for the variables used.

And satisfy the condition "A standard of measure for a physical quantity and is included as part of the x and y axes labels on a line graph."

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worty [1.4K]

Answer:

I think c

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A. How many ways can the letters of the word ALGORITHM be arranged in a row?
Tpy6a [65]

Answer:

a). The number if ways it can be arranged in a row= 362880 ways

b). 40320 ways

c). 5040 ways

Step-by-step explanation:

There are 9 alphabets in the word ALGORITHM

The number if ways it can be arranged in a row= 9!

The number if ways it can be arranged in a row= 9*8*7*6*5*4*3*2*1

The number if ways it can be arranged in a row= 362880 ways

if A and L must remain together (in order) as a unit, then we take it as 8 alphabets

= 8!

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if the letters GOR must remain together (in order) as a unit, then we have 7 alphabets units remaining

= 7!

= 7*6*5*4*3*2*1

= 5040 ways

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