Answer:
Its addition I think so the answer would we 16.7399km for both trials
Step-by-step explanation:
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
Answer:
9feet
Step-by-step explanation:
Given the path of the toy modeled by the function f(x)=−x^2+4x+5, where x is the number of feet the toy is from Emmy and f(x) is the height of the toy.
AT maximum height, the velocity of the toy will be zero. Hence;
df(x)/dx = 0
-2x + 4 = 0
-2x = -4
x = -4/-2
x = 2
Get the maximum height;
Substitute x = 2 into the given function;
f(x)=−x^2+4x+5
f(2)=−2^2+4(2)+5
f(2) = -4+8+5
f(2) = 9feet
Hence the maximum height of the toy is 9feet
Answer:
1 real solution
Step-by-step explanation:
y=2x^2−8x+8
We can use the discriminant to determine the number of real solutions
b^2 -4ac
a =2 b = -8 c=8
(-8)^2 - 4(2)(8)
64 - 64
0
Since the discriminant is 0 there is 1 real solution
>0 there are 2 real solutions
< 0 two complex solutions
