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andriy [413]
2 years ago
15

Describe the differences and similarities between the following y = 2x – 3 and y < 2x – 3

Mathematics
1 answer:
mina [271]2 years ago
8 0

Answer:

Y = -2x and Y = |-2x| correct me

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Find the x- and y-intercepts of the graph of the linear equation −x+8y=4
Andreyy89
First set the equation equal to y by adding x to each side, then divide everything by 8. then set x to zero and solve to find the y - intercept of 1/2 which is just 4/8 reduced. you get this answer because x/8 becoming 0/8 is just 0 leaving you with only 1/2. then reset the equation with x and set y to zero and solve for x to get the x- intercept of -4. you get this by subtracting 1/2 from both sides leaving you -1/2=x/8 and multiply by 8 to get -4=x

4 0
3 years ago
Encuentra tres números enteros positivos consecutivos, tal que el cuadrado del primero se igual al tercero. Determina el número
myrzilka [38]
I don’t speak Spanish
7 0
3 years ago
1. The midpoint of KL is M(5, -7). One endpoint is K(9,-7). Find the coordinates of the other endpoint L.
kirill115 [55]

Answer:

L (1, - 7 )

Step-by-step explanation:

give endpoints (x₁, y₁ ( and (x₂, y₂ )  then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )

use the midpoint formula and equate to corresponding coordinates of M

\frac{9+x}{2} = 5 ( multiply both sides by 2 to clear the fraction )

9 + x = 10 ( subtract 9 from both sides )

x = 1

and

\frac{-7+y}{2} = - 7 ( multiply both sides by 2 )

- 7 + y = - 14 ( add 7 to both sides )

y = - 7

Then L  = (1, - 7 )

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =
Georgia [21]

Answer:    \dfrac{1}{2\sqrt x}

<u>Step-by-step explanation:</u>

\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}

f(x) = \sqrt x\\

f(x+h) = \sqrt{x+h}

\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}

                   =\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)

                   =\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}

                   =\dfrac{1}{\sqrt{x+h}+\sqrt x}

                  =\dfrac{1}{\sqrt{x+0}+\sqrt x}

                  =\dfrac{1}{2\sqrt x}

4 0
3 years ago
Hey intelligent ppl... pls help?!
Lerok [7]

Answer:

YW=7 because it is congruent to the other bisector ZX.

4 0
3 years ago
Read 2 more answers
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