<u>Answer:</u> The cell potential of the cell is +0.118 V
<u>Explanation:</u>
The half reactions for the cell is:
<u>Oxidation half reaction (anode):</u> 
<u>Reduction half reaction (cathode):</u> 
In this case, the cathode and anode both are same. So,
will be equal to zero.
To calculate cell potential of the cell, we use the equation given by Nernst, which is:
![E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BNi%5E%7B2%2B%7D_%7Bdiluted%7D%5D%7D%7B%5BNi%5E%7B2%2B%7D_%7Bconcentrated%7D%5D%7D)
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
= 
= 1.0 M
Putting values in above equation, we get:


Hence, the cell potential of the cell is +0.118 V
Three quantities/variables are needed in order to calculate the amount of heat given off or absorbed during a chemical reaction are the substance, the process and the amount of substance.
When a substance in the same state absorbs heat, its temperature increases.
The amount of heat absorbed is proportional to the amount of the substance and the increase in temperature.
The amount of heat needed to raise the temperature of one gram of substance by 1°C is called the specific heat of that substance.
The specific heat of water is 4.18 J/g°C.
The amount of heat, q, absorbed by a given mass (m) of substance with specific heat, s, when its temperature increases by ΔT is given by the following formula: q = m × s × ΔT.
More about amount of heat: brainly.com/question/25603269
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Answer:
It is strongly recommended that students do NOT wear contacts lenses in the laboratory. Chemical vapors may penetrate the contact lens material and cause the lens to adhere to one's eye, which could be detrimental to the eye. Goggles are not vapor tight and do not completely eliminate this absorption.