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3 years ago

Which of the following diagrams is the correct electron dot diagram for Ne?

Chemistry

1 answer:

inna [77]3 years ago

3 0

Answer:

Explanation:

The electron dot diagram which is also known as the Lewis electron dot diagram is a diagram that shows an atom's valence electrons by placing dots, which represent the valence electrons of the element, around the elements symbol

The element for which the electron dot diagram is found = Neon, Ne

The atomic number of neon, Ne = 10

The electronic configuration of neon = 1s²2s²2p⁶

The valence shell is the outermost shell having the highest value of the coefficient of the orbitals, n = 2s²2p⁶

The number valence electrons in neon = The number of electrons in the valency shell = 2 electrons + 6 electrons = 8 electrons

The number of valence electrons in neon = 8

Therefore, the electron dot diagram for neon will have 8 dots located around the Ne symbol, which gives option B

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Enter your answer in the provided box. A person's blood alcohol (C2H5OH) level can be determined by titrating a sample of blood

Annette [7]

<u>Answer:</u> The mass percent of alcohol in blood is 0.183 %

<u>Explanation:</u>

To calculate the moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of $Cr_2O_7^{2-}$ solution = 0.05961 M

Volume of solution = 35.46 mL = 0.03546 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.05961M=\frac{\text{Moles of }Cr_2O_7^{2-}}{0.03546L}\\\\\text{Moles of }Cr_2O_7^{2-}=(0.05961mol/L\times 0.03546L)=2.11\times 10^{-3}mol$

The given chemical reaction follows:

$16H^+(aq.)+2Cr_2O_7^{2-}(aq.)+C_2H_5OH(aq.)\rightarrow 4Cr^{3+}(aq.)+2CO_2(g)+11H_2O(l)$

By Stoichiometry of the reaction:

2 moles of dichromate ions react with 1 mole of ethanol.

So, $2.11\times 10^{-3}mol$ of dichromate ions will react with = $\frac{1}{2}\times 2.11\times 10^{-3}=1.06\times 10^{-3}mol$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of ethanol = $1.06\times 10^{-3}mol$

Molar mass of ethanol = 46.07 g/mol

Putting values in above equation, we get:

$1.06\times 10^{-3}mol=\frac{\text{Mass of ethanol}}{46.07g/mol}\\\\\text{Mass of ethanol}=(1.06\times 10^{-3}mol\times 46.07g/mol)=0.0488g$

To calculate the mass percent of ethanol in blood, we use the equation:

$\text{Mass percent of ethanol}=\frac{\text{Mass of ethanol}}{\text{Mass of blood plasma}}\times 100$

Mass of blood plasma = 26.60 g

Mass of ethanol = 0.0488 g

Putting values in above equation, we get:

$\text{Mass percent of ethanol}=\frac{0.0488g}{26.60g}\times 100=0.183\%$

Hence, the mass percent of alcohol in blood is 0.183 %

5 0

3 years ago

Which process is most responsible for leaving salt molecules in ocean water?

Elenna [48]

Desalination is a process that takes away mineral components from saline water.

4 0

3 years ago

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Why is "Glutathione"considered as a reducing agent?

Norma-Jean [14]

Biologically, GSH reduces the disulfide bonds formed within cytoplasmic proteins to cysteines and reacts to other oxidized GSH to an oxidized form of glutathione disulfide (GSSG), also called L(-)-glutathione. It is oxidized by glutathione reductase by using NADPH as an electron donor

3 0

3 years ago

How many moles of gas would you have if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature

seraphim [82]

Answer: There are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

Explanation:

Given: Volume = 38.0 L

Pressure = 1430 mm Hg (1 mm Hg = 0.00131579 atm) = 1.9 atm

Temperature = 273.15 K

Using ideal gas equation, the moles of gas will be calculated as follows.

$PV = nRT\\$

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T =temperature

Substitute the values into above formula as follows.

$PV = nRT\\1.9 atm \times 38.0 L = n \times 0.0821 L atm/mol K \times 273.15 K\\n = \frac{1.9 atm \times 38.0 L}{0.0821 L atm/mol K \times 273.15 K}\\= 3.2 mol$

Thus, we can conclude that there are 3.2 moles of gas if you have a volume of 38.0 L under a pressure of 1430 mmHg at standard temperature.

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3 years ago

Determine the oxidation state a manganese in each of the following structures. a) Mn0₂ b) Mn2O7 C) KMnO4 .

irina1246 [14]

Explanation:

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6 0

2 years ago