To solve this problem you must apply the proccedure shown below:
1- You must apply the following formula:
![R=yo-yp](https://tex.z-dn.net/?f=%20R%3Dyo-yp%20)
Where
is the residual,
is the observed value
and
is the predicted value
.
2- You only need to substitute the
into the equation
and then, you must apply the formula for calculate the residual:
![y=2.5(5)-1.5\\ y=11](https://tex.z-dn.net/?f=%20%20y%3D2.5%285%29-1.5%5C%5C%20y%3D11%20)
![R=12-11\\ R=1](https://tex.z-dn.net/?f=%20R%3D12-11%5C%5C%20R%3D1%20)
The answer is: The residual is ![1](https://tex.z-dn.net/?f=%201%20)
Step-by-step explanation:
Hey there!
By looking through figure, l and m are parallel lines and a transversal line passes through the lines.
Now,
7x + 12° = 12x - 28°( alternate angles are equal)
12°+28° = 12x - 7x
40° = 5x
![x = \frac{40}{5}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B40%7D%7B5%7D%20)
Therefore, x = 8°
Now,
12x - 28° + 9y - 77 = 180° ( being linear pair)
12×8° - 28° + 9y -77° = 180°
96° - 28° + 9y - 77° = 180°
-9 + 9y = 180°
9y = 180° + 9°
y = 189°/9
Therefore, y = 21°
<u>There</u><u>fore</u><u>,</u><u> </u><u>X </u><u>=</u><u> </u><u>8</u><u>°</u><u> </u><u>and</u><u> </u><u>y</u><u>=</u><u> </u><u>2</u><u>1</u><u>°</u><u> </u><u>.</u>
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
F(x)=10x-7
f(0)=10(0)-7
f(0)=(0)-7
f(0)=-7
Answer:
C. 7/2
Step-by-step explanation:
To get the number of 1/2 cup servings in 7/4 cups of rice you need to divide 7/4 by 1/2
7/4 ÷ 1/2
7/4×2/1----------------------multiplied by the reciprocal
14/4-----------------simplify by dividing both parts by 2
7/2----------------simplest fraction form
Answer:
![3-\sqrt{10}](https://tex.z-dn.net/?f=3-%5Csqrt%7B10%7D)
Step-by-step explanation:
We are given an expression and are asked to find what it equals. We can see that the two square roots are being multiplied, therefore they follow the same standard as any multiplication problem, do as followed :
![\sqrt{5} *\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B5%7D%20%2A%5Csqrt%7B2%7D)
![\sqrt{10}](https://tex.z-dn.net/?f=%5Csqrt%7B10%7D)
Since a square root and constant number are different terms, we cannot combine them together, therefore leave as is :
![3-\sqrt{10}](https://tex.z-dn.net/?f=3-%5Csqrt%7B10%7D)