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Pavel [41]
3 years ago
11

Algebraic expression for 3 more than x

Mathematics
2 answers:
lisov135 [29]3 years ago
7 0

Answer:

3 + x

Step-by-step explanation:

"More than" means addition. 3 more than x is saying 3 plus x. In an algebraic expression, this would look like:

3 + x

Mkey [24]3 years ago
6 0

Answer:

For example, the phrase "3 more than an unknown number" becomes the mathematical expression "x + 3." Because the unknown number has no explicitly stated value, we label it with a variable x. To get a value three more than x, simply add 3 to it.

hope it helps ya mate. ~^~

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Step-by-step explanation:

g(t)=t^2 - t

f(x) = (1 + x)

g(f(x)) = f(x)^2 - f(x)

g(f(x)) = (x + 1)^2 - x - 1

g(f(0)) = (0 +1)^2 - x - 1

g(f(0)) = 1 - 1  - 1 = -1

================================

f(x) = 1 + x

f(g(t)) = 1 + g(t)

f(g(t)) = 1 + t^2 - t

f(g(0)) = 1 + 0 - 0

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What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)
svlad2 [7]

Answer:

The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

Step-by-step explanation:

Given : Expression 7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

To Simplified : The expression

Solution :  

Step 1 - Write the expression

7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}

Step 2- Simplify the roots and re-write as

16=2^3\times2 and 8=2^3

7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}

Step 3- Solve the multiplication

7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}

Step 4- Taking \sqrt[3]{2x} common from first two terms

\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}

\sqrt[3]{2x}-6\sqrt[3]{x}

Therefore, The simplified form of the expression is \sqrt[3]{2x}-6\sqrt[3]{x}

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