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3 years ago

Algebraic expression for 3 more than x

Mathematics

2 answers:

lisov135 [29]3 years ago

7 0

Answer:

3 + x

Step-by-step explanation:

"More than" means addition. 3 more than x is saying 3 plus x. In an algebraic expression, this would look like:

3 + x

Mkey [24]3 years ago

6 0

Answer:

For example, the phrase "3 more than an unknown number" becomes the mathematical expression "x + 3." Because the unknown number has no explicitly stated value, we label it with a variable x. To get a value three more than x, simply add 3 to it.

hope it helps ya mate. ~^~

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8_murik_8 [283]

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3 years ago

Eli read four more biographies than historical fiction book during the semester. He also read two fewer mysteries than historica

9966 [12]

Answer: Eli read 3 historical fiction books , 7 biographies and 1 mystery book.

Step-by-step explanation:

Let x be the number of historical fiction books Eli read.

Then, Number of biographies he read = x+4

Number of mysteries he read = x-2

If he read a total of eleven books during the semester , then we have the following equation :

$x+x+4+x-2=11$

$\\\\\Rightarrow\ 3x+2=11$

$\\\\\Rightarrow\ 3x=9$ (Subtract 2 from both sides )

$x=3$ (Divide both sides by 3)

Therefore , Number of historical fiction books Eli read = 3

Number of biographies he read = 3+4=7

Number of mysteries he read =3-2=1

Hence, Eli read 3 historical fiction books , 7 biographies and 1 mystery book.

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3 years ago

Read 2 more answers

What is the extraneous solution found in solving the equation log2 4x + log₂ (x + 1) = 3

yan [13]

Answer:

x = -2

Step-by-step explanation:

We are given the logarithmic base 2 equation of:

$\displaystyle{\log_2 (4x) + \log_2 (x+1) = 3}$

Apply logarithm property of addition where:

$\displaystyle{\log_a M + \log_a N = \log_a MN}$

Therefore, we will write new equation as:

$\displaystyle{\log_2 [4x(x+1)] = 3}$

Apply logarithm to exponential form using:

$\displaystyle{\log_a M = N \to a^N = M}$

Thus, another new rewritten equation is:

$\displaystyle{2^3 = 4x(x+1)}\\\\\displaystyle{8 = 4x(x+1)}\\\\\displaystyle{2=x(x+1)}$

Expand the expression in and arrange the terms in quadratic expression:

$\displaystyle{2=x^2+x}\\\\\displaystyle{0=x^2+x-2}\\\\\displaystyle{x^2+x-2=0}$

Solve for x:

$\displaystyle{(x+2)(x-1)=0}\\\\\displaystyle{x=-2,1}$

These are potential solutions to the equation. To find extraneous solution, you’ll have to know the domain of logarithm function. We know that logarithm’s domain is defined to be greater than 0. Henceforth, anti-logarithm must be greater than 0.

( 1 ) 4x > 0, x > 0

( 2 ) x + 1 > 0, x > -1

Therefore, our anti-log must be greater than 0, so any solutions that are equal or less than 0 will be considered as extraneous solution.

Hence, x = -2 is the extraneous solution.

7 0

2 years ago

Please answer correctly !!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!

8090 [49]

Answer:

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4 years ago