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Tpy6a [65]
3 years ago
9

Which inequality represents the graph below?

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0

Answer:I need to see the graph to answer your question

Step-by-step explanation:

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If you know how to do it, please help me out :)
Artemon [7]

Answer:

Answer in explanation.

Step-by-step explanation:

Lets take

y =  \frac{3}{4} x - 5

as L1.

Take L2 the line perpendicular to L1.

Standard form of equation of line:

y=mx+c, where m = slope and c = y-intercept.

Since L1 and L2 are perpendicular,

mL1 x mL2 = -1

Substitute mL1 into the equation,

3/4 x mL2 = -1

mL2 = -1 ÷ 3/4

mL2 = -4/3

L2 : y = mx+ c

Substitute y = 6, x = 8 and m = -4/3 into the equation,

6 =  -  \frac{4}{3} (8) + c \\ 6 = -  \frac{32}{3}  + c \\ c = 6 +  \frac{32}{3}  \\  = 16 \frac{2}{3}

therefore L2:

y =  -  \frac{4}{3}x   + 16 \frac{2}{3}

Lets take L3 as the line parallel to L1.

Since L3 and L1 are parallel,

mL3 = mL1 = 3/4

equation of line: y = mx+c

substitute y = 6, x = 8 and m = 3/4 into equation.

6 = ( \frac{3}{4} )(8) + c \\ 6 = 6 + c \\ c = 6 - 6 \\  = 0

therefore L3:

y =  \frac{3}{4} x

8 0
2 years ago
Which of the following inequalities does the graph represent?
Romashka-Z-Leto [24]

For this case we must indicate the inequality represented in the graph.

It is noted that we have a closed point at -1, so the inequality at that point contains equality and is represented by "[". On the other hand, we observe an open point at +3, so inequality does not include equality (does not include +3) and is represented as ")".

So, the interval of the graph is:

[-1,3)

This is equivalent to:

-1 \leq t

Answer:

Option B

4 0
3 years ago
Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be
Rina8888 [55]
This is a combination problem.

Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.

The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.

This is the formula I used because the order is not important and repetition is not allowed. 

Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.

numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960

Combination = 39,916,800 / 120,960 = 330

There are 330 ways that the instructor can choose 4 students for the first group


8 0
3 years ago
Read 2 more answers
On a math test the students are given a right triangle one ofbthe acute angles has a measure of 41 one student says that the mea
BaLLatris [955]
The error is that the student measured the wrong side. Acute angles are less than 90 degrees. So it isn’t possible for the measure to be over 90. The correct measure is 49
6 0
2 years ago
Can someone help me with this?
faltersainse [42]

Answer:

I think it's graph 2 hope that helps

7 0
1 year ago
Read 2 more answers
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