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STatiana [176]
3 years ago
7

The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1=-5\\ n=10\\ a_{10}=13 \end{cases} \\\\\\ a_{10}=a_1+(10-1)d\implies 13=-5+(10-1)d \\\\\\ 13=-5+9d\implies 18=9d\implies \cfrac{18}{9}=d\implies \boxed{2=d}

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Help please its for school
Alex

Answer:

68.302

Step-by-step explanation:

68302/1000=68.302

hope this helps :)

8 0
2 years ago
Read 2 more answers
Multiply each equation by a constant that would help to eliminate the y terms.
Zinaida [17]

Answer:

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

Step-by-step explanation:

Given:

2x-5y=-21         ......................Equation ( 1 )

3x-3y=-18         ......................Equation ( 2 )

To Find:

Expression after multiplying to eliminate y term,

Solution:

So to eliminate 'y' term we need to multiply equation 1 by a constant 3 and equation 2 by a constant -5,  such that equations  becomes

3(2x-5y)=3\times -21\\\\6x-15y=-63 .....( 1 )

-5(3x-3y)=-5\times -18\\\\-15x+15y=90  .....( 2 )

so now by adding new equation one and two we can eliminate y term that means -15y and +15y will get cancel,

Therefore the required resulting equation is

6x-15y=-63\\-15x+15y=90

6 x minus 15 y = negative 63.

Negative 15 x + 15 y = 90

3 0
3 years ago
Read 2 more answers
Please help i will give brainliest
inn [45]

Answer:

y = -3

Step-by-step explanation:

6 0
3 years ago
For what values of k does the graph of y=-2x^2+5x+k not cut the x axis
goldenfox [79]
The answer is 4 because there r three 3 2s
6 0
3 years ago
SOMEONE HELP PLEASE! ASAP!
Luba_88 [7]
When two lines intersect, the angles across from the intersection (the "X") are congruent (equal), and referred to as "vertical angles."
So by the rule of vertical angles are congruent, we can set them equal:
{x}^{2}  - 6x = 1\div2 \: x + 42 \\  {x}^{2}  - 6x - 1 \div 2 \: x = 42 \\  {x}^{2}  - 6.5x = 42
{x}^{2}  - 6.5x - 42 = 0 \\ multiply \: both\: sides \: by \: 2 \: to \: get \\ rid \: of \: the \: decimal \\ 2({x}^{2}  - 6.5x - 42) = 2(0)
2 {x}^{2}  - 13x - 84 = 0
to factor we need the factors of 84:
1×84, 2×42, 3×28, 4×21, 6×14
Now we need one of those factors ×2 ( from the x^2 term) minus the other factor to equal 13 (the middle term)
it turns out that if we use 4×21: 4×2 = 8
and 21-8 = 13. Woohoo! we got it
So now we have:
2 {x}^{2}  - 13x - 84 = 0 \\ (2x - 21)(x + 4) = 0
Now set each factor = 0
1) 2x - 21 = 0 and 2) x + 4 = 0
1) 2x - 21 = 0, 2x = 21, x = 21/2 = 10.5
2) x + 4 = 0, x = -4

Now we plug in each answer to check:
1) x = 10.5
{x}^{2}  - 6x =  {(10.5)}^{2}  - 6(10.5) \\  = 110.25 - 63 = 47.25
1/2x + 42 = 1/2(10.5) + 42 = 5.25 + 42 = 47.25
47.25 = 47.25
BAM SO IT LOOKS LIKE THAT'S IT!!
But let's check 2) first:
2) x = -4
{( - 4)}^{2}  - 6( - 4) = 16 + 24 = 40
1/2x + 42 = 1/2(-4) + 42 = -2 + 42 = 40
40 = 40, so both work!!
But it asks for m<1, and <1 is supplementary because it lies on same line, meaning the sum of both = 189
Therefore m<1 = 180 - 47.25 = 132.75°
OR m<1 = 180 - 40 = 140°


6 0
3 years ago
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