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adell [148]
3 years ago
9

porque una roca pequeña se hunde en el agua mientras los barcos no se hunden apesar de ser tan pesados​

Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

Step-by-step explanation: una roca se unde porque aunq tiene una forma solida igualmente que un barco, la roca no tiene aire dentro de ella, a diferencia del barco que es hueco por dentro, contiene aire causando que flote y no pueda hundirse

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Order numbers 11/8,1.405, and1.45 smallest to largest
Diano4ka-milaya [45]

Step-by-step explanation:11/8 is 12.5 goes into one hundred 8 times so 12 x 11 is 137.5so then turn decimals to a percent 1.405 is 140.5 1.45 is 145 so the it is 137.5 140.5,145

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3 years ago
What is question 9please please help
Serggg [28]
The answer would be c !
8 0
3 years ago
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Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi
Zanzabum

1. N is a midpoint of the segment KL, then N has coordinates

\left(\dfrac{x_K+x_L}{2},\dfrac{y_K+y_L}{2} \right) =\left(\dfrac{0+2a}{2},\dfrac{2b+0}{2} \right) =(a,b).

2. To find the area of △KNM, the length of the base MK is 2b, and the length of the height is a. So an expression for the area of △KNM is

A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.

4. Comparing the expressions for the areas you have that the area A_{KMN} is equal to the area A_{MNL}. This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

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3 years ago
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sergiy2304 [10]
1296 is your answer.
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3 years ago
Segment CW is congruent to segment MQ
Fiesta28 [93]

Answer:

The true congruence statement is CW ≅ MQ ⇒ 2nd answer

Step-by-step explanation:

All the radii in the circle are congruent

From the attached figure

In circle B

∵ W, C, Q, and M lie on the edge of the circle

∴ BW, BC, BQ, and BM are radii

∵ All the radii in the circle are congruent

∴ BW ≅ BC ≅ BQ ≅ BM

∵ CW ≅ MQ ⇒ Given

∴ The true congruence statement is CW ≅ MQ

5 0
3 years ago
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