Well
You want to calculate the interest on $1000 at 3.5% interest per month after 3 year(s).
The formula we'll use for this is the simple interest formula, or:
Where: P is the principal amount, $1000.00.
r is the interest rate, 3.5% per month, or in decimal form, 3.5/100=0.035.
t is the time involved, 3....year(s) time periods.
Since your interest rate is "per month" and you gave your time interval in "year(s)" we need to convert your time interval into "month" as well.
Do this by multiplying your time, 3 year(s), by 12, since there's 12 months in 1 year.
So, t is 36....month time periods.
To find the simple interest, we multiply 1000 × 0.035 × 36 to get that:
The interest is: $1260.00
Hope i could help
Answer:
y = 
Step-by-step explanation:
multiply 
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simplify:
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subract from both sides:
y =
Answer:
Each project has 2.500 man-hours
Step-by-step explanation:
Available man hours: 5000
For two projects Costs $
X: project A 10
Y: project B 12
Approach:
X + Y = 5000 => X = 5000 - Y
10 * X + 12 * Y = 55000
replacing:
10 * (5000 - Y) + 12 * Y = 55000
50000 - 10 * Y + 12 * Y = 55000
2 * Y = 55000 - 50000
Y = 5000/2
Y = 2500
For X:
X = 5000 - 2500
X = 2500
The number of hours available for each project are:
Projects Man hours
X: project A 2500
Y: project B 2500
Answer:
<u>length×base×height</u>
3
= <u>10×10×8</u>
3
= <u>8</u><u>0</u><u>0</u>
3
= 266.67cm³
