Find the solution of y = 6x + 1 for x = 5

Write an equivalent expression for (x - 11)(x + 9).

vodka [1.7K]

Answer:

x²-2x-99

Step-by-step explanation:

(x-11)(x+9) - foil method

x times x = x squared

x times 9 = 9x

-11 times x = -11x

-11 times 9 = -99

x squared + 9x + 11x + -99

x squared-2x-99

7 0

2 years ago

How can I solve this?<br>Please use the simplest format

IgorLugansk [536]

Answer:

option D is true.

Step-by-step explanation:

The right-angled triangle is shown.

From the right-angled triangle,

The angle Ф = 60°

We know that the trigonometric ratio

tan Ф = opposite / adjacent

opposite = 4

adjacent = n

Thus,

tan 60 = 4 / n

√3 = 4/n

n = 4/√3

Thus,

n = 4/√3

= (4 × √3) / (√3 × √3)

= 4√3 / 3

Thus,

n = 4√3 / 3

Using Pythagorean theorem

m = √n²+4²

$m=\sqrt{\left(4\cdot \frac{\sqrt{3}}{3}\right)^2+4^2}$

$m=\sqrt{\frac{4^2}{3}+4^2}$

$m=\sqrt{\frac{64}{3}}$

$m=\frac{8}{\sqrt{3}}$

$m=\frac{8\sqrt{3}}{3}$

Thus,

$m=\frac{8\sqrt{3}}{3}$

n = 4√3 / 3

Therefore, option D is true.

3 0

2 years ago

How do I solve this problem

tino4ka555 [31]

Answer:

0.6

Step-by-step explanation:

2x3 add 1 power of 10 to the 3 you get 6 and now you just remove/divide the power of 10 you added and you get .6

7 0

3 years ago

3. A kite is aloft at the end of a 1500 foot string. The string make an angle of 43° with the

sineoko [7]

Answer:

$h= 1500\,*\,sin(43^o)$

Step-by-step explanation:

Notice that there is a right angle triangle formed with sides as follows:

hypotenuse is the actual 1500 ft string. The acute angle 43 degrees is opposite to the segment that represents the height of the kite from the ground. Therefore, the trigonometric ratio that we can use to find that opposite side to the given angle, is the sine function as shown below:

$sin(43^o) = \frac{opposite}{hypotenuse} \\sin(43^o) = \frac{opposite}{1500}\\opposite = 1500\,*\,sin(43^o)\\h= 1500\,*\,sin(43^o)$

8 0

3 years ago

Find the equation of the line passing through the given points. Express the equation in standard form.

Artyom0805 [142]

We want to write the equation of the line passing through these two points in standard form.

First, we are going to do this in slope intercept form and then change the form to standard form, which is Ax + By = C

We will use the equation y = mx + b, and since we are given two points on the line we are going to determine the slope of the line by determining the change in the y coordinates

m = y sub2 - y sub1 divided by the change in the X coordinates x sub2 – x sub1

We will start by determining the slope

(1, -6) the 1 is x sub 1 and the 6 is y sub 1

(-7, 2) the -7 is x sub 2 and the 2 is y sub 2

2 - (-6) = 8

-7 -1 = -8

so equation now is m = -1

So now again referring back to the slope intercept of the line we now know y = -1 + b. We still have to determine b and the y intercept, and we can do this by using one of the given points and substituting in the value for y and x, and then solve for b. Since these points are on the line, they must satisfy this equation. If we use the first coordinates, we would substitute 1 for x and -6 for y.

-6 = -1 times x, which is 1 + b

b = -5

construct the line equation y = mx + b where m = -1 & b = -5

In slope intercept form the equation would be y = -x - 5

Now we want to write this in standard form now. We have to deal with two things. The x and y terms have to be on the left side and A and B and C have to be integers.

The standard form of a linear equation is Ax + By=CA x + By = C . Move all terms containing variables to the left side of the equation.

Add x to both sides of the equation.

y + x = -5

Reorder y & x

x + y = -5

3 0

3 years ago