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pychu [463]
3 years ago
6

What do you need to do to solve the problem? x/5 = 8 helppppppppppppp

Mathematics
2 answers:
Dmitrij [34]3 years ago
4 0

Answer:

x=40

Step-by-step explanation:

x/5 = 8

since a fraction is just like dividing you need to do the opposite

you need to multiply by 5 on both sides

x=40

qaws [65]3 years ago
4 0

Answer:

x = 40

Step-by-step explanation:

Multiply 5 to both sides

\frac{x}{5} = 8

\frac{x}{5} × 5 = 8 × 5

x = 40

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The value of the digit nine in that number is ten, the nine os in the tens place
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Explain how to find 27% of 16 using multiplication by a
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How many solutions does the equation 4q + 8 = 6 + 2 + 4q have?
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4q-4q=8-8
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None.
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Find the area of the shaded region. H=8 W=8 L=10
Wittaler [7]
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It is going to be half the area of the rectangle:

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Hope this helped :))
6 0
3 years ago
QUESTION 1
SVEN [57.7K]

Answer:

1)

1st Error: In going from Step 3 to Step 3.

Reason: Negative sign is not distributed inside the brackets.

2nd Error: In going from Step 5 to Step 6

Reason: Sign of the number is not changed while moving to other side of inequality,

2)

a) 12=-4(-6x-3) and x+5=-5x+5

b) -(7-4x)=9 and 5x+34=-2(1-7x) and -8=-(x+4)

Step-by-step explanation:

Question 1)

The given inequality is:

\frac{5}{12}-\frac{x-3}{6} \leq  \frac{x-2}{3}

<u>Step 1: Making the denominators common for all fractions</u>

\frac{5}{12}-\frac{2}{2} \times \frac{x-3}{6} \leq \frac{4}{4} \times \frac{x-2}{3}

This step is done correctly in the given solution.

<u>Step 2: Simplifying </u>

\frac{5}{12}-\frac{2x-6}{12}\leq \frac{4x-8}{12}

This step is done correctly in the given solution

<u>Step 3: Multiplying both sides by 12, and simplifying.</u>

5-(2x-6)\leq 4x-8\\\\ 5-2x+6\leq 4x-8

First error is made in this step. While opening the brackets, the negative sign should be distributed inside the bracket, which will change the signs.

<u>Step 4: Simplification:</u>

11-2x\leq 4x-8

<u>Step 5: Moving Common terms to one side and simplifying</u>

-2x-4x\leq -8-11\\\\ -6x\leq -19

Error was made in this step. When a number is moved to other side, its sign will be changed.

<u>Step 6: Dividing both sides by -6</u>

x\geq \frac{19}{6}

Conclusion:

1st Error: In going from Step 3 to Step 3.

Reason: Negative sign is not distributed inside the brackets.

2nd Error: In going from Step 5 to Step 6

Reason: Sign of the number is not changed while moving to other side of inequality,

Question 2:

In the Equation 2: 12=-4(-6x-3), when -4 will be multiplied inside the brackets, the 12 on eft hand side will cancel the 12 that will appear on right hand side, giving a result that will lead to x = 0.

Same is the case with Equation 6: x+5=-5x+5, 5 on both sides will cancel out leaving x = 0.

So, 2nd and 6th equations will have the same solution.

In Equation 1, on expanding the bracket and moving 7 to other side, we get a relation: 4x = 16

In Equation 3, on simplifying the right hand side, and carrying common terms to one side, we get the relation: - 9x = -36

In Equation 5, on expanding the bracket and simplifying the relation is reduced to 4 = x

It can be observed that all these 3 equations have the same solution i.e. x = 4

So, the following set of Equations have the same solution:

a) 12=-4(-6x-3) and x+5=-5x+5

b) -(7-4x)=9 and 5x+34=-2(1-7x) and -8=-(x+4)

6 0
3 years ago
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