Question

In the interval 0° < x < 360°, find the values of x for which sin x = 0.6691 Give your answer tot he nearest degree

Answer 1

Answer:

x are 42 and 138degees

Step-by-step explanation:

Given the expression  sin x = 0.6691

sin x = 0.6691

Take the sin inverse of both sides

sin⁻¹(sin x) =  sin⁻¹(0.6691 )

x = sin⁻¹(0.6691 )

x = 41.99

x = 42 degrees (to the nearest degree)

Since sin theta is positive in the second quadrant;

x = 180 -theta

x = 180 - 42

x = 138degrees

Hence the value of x are 42 and 138degees