Answer:
...
against the wind, an airplane travels 3640 km in 7 hours.
with the wind, the same plane travels 6000 km in 6hrs.
...
let speed of plane in still air be x mph
speed of wind be y mph.
..
t=d/r
..
against wind speed = x-y mph
with wond speed = x=y mph
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3640/(x-y)=7
3640 = 7x-7y
/7
520=x-y.....................1
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6000/x+y = 6
6000 = 6x+6y
/6
1000=x+y.....................2
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Add (1) & (2)
2x=1520
/2
x=760 mph speed of plane in still air
...
plug value of x in 2
1000=760+y
100-760=y
240 = y
240 mph speed of wind
Answer:
w => -4
w =<9
Step-by-step explanation:
Answer:
Step-by-step explanation:
In this equation what is strange is probably using the letter a as the unknown, but this is a matter of choice we could have calle y or z for that matter. Then we will treat it ans any other equation and solve it.
-11 -5a = 6(5a+4)
-11 -5a= 30a + 24
-11 - 24 = 30a + 5a (placing the unknown a in the rght side and the numbers in the left to solve the equation)
- 35 = 35a
-35/35 = a
- 1= a
Years and years a long time ahead
Answer:
Option A) Bethany is correct because consecutive odd integers will each have a difference of two
Step-by-step explanation:
The sum of 3 consecutive odd integers is 91. Let the first odd integer is x. The next odd integer will be obtained by adding 2 in x i.e. (x + 2). The third odd integer will be obtained by adding 2 in the second odd integer i.e. (x + 2) + 2 = x + 4
So, the 3 odd integers will be:
x , (x+2) and (x+4)
Their sum is given to be 91. So we can write:
x + (x+2) + (x+4) = 91
Hence, we can conclude that: Bethany is correct because consecutive odd integers will each have a difference of two.
Other options are not correct because consecutive odd integers always increase by 2. For example, the next odd integer after 1 is 3, which is obtained by adding two, similarly the next odd will be 5 and so on.