3 years ago

Which pair of triangles is Alessandra referring to, and which criterion should she use for establishing congruence?

Mathematics

1 answer:

Doss [256]3 years ago

8 0

Answer:

△ABCtriangle and △CDAtriangle, by side-angle-side

Step-by-step explanation:

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What is the simplified form of 4x plus 2 over x plus 5 minus the fraction 3x plus 1 over x plus 5?

viva [34]

We have that

[(4x+2)/(x+5)]-[(3x+1)/(x+5)]
<span>They have common denominators, so just add the numerators like normal fractions:</span>
=[(4x+2)-(3x+1)]/(x+5)
=[(4x+2-3x-1)]/(x+5)
=[(x+1)]/(x+5)

the answer is
(x+1)/(x+5)

4 0

3 years ago

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ANSWER FAST PLZ 65 POINTS!!!!!!!!!!!!!!!!!!

Snezhnost [94]

Area of a circle is found using the formula: A = PI x r^2 where r is the radius of the circle, which is half the diameter.

Using the information in the problem you have:

A= PI x 15^2

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3 years ago

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If log(x + y) = log 3 + ½log x + ½log y, prove that x² + y² = 7xy

Free_Kalibri [48]

Answer:

See Explanation

Step-by-step explanation:

$log(x + y) = log3 + \frac{1}{2} logx+ \frac{1}{2} logy \\ \\ log(x + y) = log3 + logx ^{\frac{1}{2}} + logy ^{\frac{1}{2}}\\ \\ log(x + y) = log3 + log(xy) ^{\frac{1}{2}} \\ \\ log(x + y) = log[3(xy) ^{\frac{1}{2}}] \\ \\ x + y = 3(xy) ^{\frac{1}{2}} \\ \\ squaring \: both \: sides \\ {(x + y)}^{2} = \bigg(3(xy) ^{\frac{1}{2}} \bigg)^{2} \\ \\ {x}^{2} + {y}^{2} + 2xy = 9xy \\ \\ {x}^{2} + {y}^{2} = 9xy - 2xy \\ \\ \purple{ \bold{{x}^{2} + {y}^{2} = 7xy}} \\ thus \: proved$