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Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:
Compute the degrees of freedom as follows:
Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:
*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Divide by 21 to put the equation in intercept form.
x/(21/9) + y/(-21/7) = 1
x/(7/3) + y/(-3) = 1
The x-intercept is (7/3, 0)
The y-intercept is (0, -3)
The 3rd choice is appropriate.
x/(21/9) + y/(-21/7) = 1
x/(7/3) + y/(-3) = 1
The x-intercept is (7/3, 0)
The y-intercept is (0, -3)
The 3rd choice is appropriate.