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Lapatulllka [165]
3 years ago
13

You are moving to an area where DSL will be available in the next six months. Which method of internet connectivity should you i

mplement until DSL is available if your existing connectivity needs are minimal
Computers and Technology
1 answer:
netineya [11]3 years ago
7 0

Answer:

Answer would be, PSTN (public switched telephone network)

You might be interested in
Which type of ICS facility is used to temporarily position and account for personnel, supplies, and equipment awaiting assignmen
Black_prince [1.1K]

Answer:

C. Staging Area

Explanation:

According to my research on different ICS facilities, I can say that based on the information provided within the question the facility being described here is called a Staging Area. Like mentioned in the question a staging area is a location set up at an incident where resources and personnel can be placed while waiting on instructions to proceed with an operation or assignment.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
A ____ is a structure that allows repeated execution of a block of statements.
Leokris [45]

Answer:

loop

Explanation:

Loop is the one which is used to execute the specific statement again and again until the condition is true.

In the programming, there are 3 basic loop used.

1. for loop

<u>Syntax:</u>

for(initialization, condition, increment/decrement)

{

  statement;

}

the above statement execute until the condition in the for loop true when it goes to false, the loop will terminate.

2. while loop

<u>Syntax:</u>

initialization;

while(condition)

{

  statement;

increment/decrement;

}

it is work same as for loop and the increment/decrement can be write after or before the statement.

3. do while

syntax:

initialization;

do

{

   statement;

   increment/decrement;

}while(condition);

here, the statement execute first then, it check the condition is true or not.

so, if the condition is false it execute the statement one time. this is different with other loops.

3 0
3 years ago
Read 2 more answers
Some of the ways we can resolve IPv4 address shortage
tekilochka [14]

Answer:

NAT

Proxy

IPv6

Explanation:

Network Address Translation (NAT) allows a local area network (LAN) to connect to the internet using only one external IP address. The LAN addresses (typically 192.168.x.x) can be used over and over again.

A proxy is a computer that makes requests to the internet on behalf of the computers on a LAN. It is a more restricted flavour compared to the NAT, but the effect is the same.

IPv6 is a new addressing scheme that will use a 48 bits address space rather than a 32 bits address space of IPv6, and that would provide plenty of addresses.

7 0
3 years ago
The ________ of a cpu dictates how many instructions the cpu can process each second.
makkiz [27]
Gigahertz is the correct answer I believe.
My processor is a i5-6600k with 3.5ghz so assuming GHz is the speed I believe it would be gigahertz
3 0
4 years ago
Building a String Library
maw [93]
Code:

def myAppend( str, ch ):
# Return a new string that is like str but with
# character ch added at the end
return str + ch

def myCount( str, ch ):
# Return the number of times character ch appears
# in str.

# initiaalizing count with 0
count = 0

# iterating over every characters present in str
for character in str:
# incrementing count by 1 if character == ch
if character == ch:
count += 1

# returning count
return count


def myExtend( str1, str2 ):
# Return a new string that contains the elements of
# str1 followed by the elements of str2, in the same
# order they appear in str2.

# concatenating both strings and returning its result
return str1 + str2

def myMin( str ):
# Return the character in str with the lowest ASCII code.

# If str is empty, print "Empty string: no min value"
# and return None.
if str == "":
print("Empty string: no min value")
return None

# storing first character from str in char
char = str[0]

# iterating over every characters present in str
for character in str:
# if current character is lower than char then
# assigning char with current character
if character < char:
char = character
# returning char
return char


def myInsert( str, i, ch ):
# Return a new string like str except that ch has been
# inserted at the ith position. I.e., the string is now
# one character longer than before.

# Print "Invalid index" if
# i is greater than the length of str and return None.

if i > len(str):
print("Invalid index")
return None

# str[:i] gives substring starting from 0 and upto ith position
# str[i:] gives substring starting from i and till last position
# returning the concatenated result of all three
return str[:i]+ch+str[i:]

def myPop( str, i ):
# Return two results:
# 1. a new string that is like str but with the ith
# element removed;
# 2. the value that was removed.
# Print "Invalid index" if i is greater than or
# equal to len(str), and return str unchanged and None
if i >= len(str):
print("Invalid index")
return str, None

# finding new string without ith character
new_str = str[:i] + str[i+1:]

# returning new_str and popped character
return new_str, str[i]

def myFind( str, ch ):
# Return the index of the first (leftmost) occurrence of
# ch in str, if any. Return -1 if ch does not occur in str.

# finding length of the string
length = len(str)

# iterating over every characters present in str
for i in range(length):
# returning position i at which character was found
if str[i]==ch:
return i
# returning -1 otherwise
return -1


def myRFind( str, ch ):
# Return the index of the last (rightmost) occurrence of
# ch in str, if any. Return -1 if ch does not occur in str.

# finding length of the string
length = len(str)

# iterating over every characters present in str from right side
for i in range(length-1, 0, -1):
# returning position i at which character was found
if str[i]==ch:
return i
# returning -1 otherwise
return -1

def myRemove( str, ch ):
# Return a new string with the first occurrence of ch
# removed. If there is none, return str.

# returning str if ch is not present in str
if ch not in str:
return str

# finding position of first occurence of ch in str
pos = 0

for char in str:
# stopping loop if both character matches
if char == ch:
break
# incrementing pos by 1
pos += 1

# returning strig excluding first occurence of ch
return str[:pos] + str[pos+1:]

def myRemoveAll( str, ch ):
# Return a new string with all occurrences of ch.
# removed. If there are none, return str.

# creating an empty string
string = ""

# iterating over each and every character of str
for char in str:
# if char is not matching with ch then adding it to string
if char!=ch:
string += char
# returning string
return string

def myReverse( str ):
# Return a new string like str but with the characters
# in the reverse order.

return str[::-1]
6 0
3 years ago
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