Answer:
The output is "<class 'str'> ".
Explanation:
In the given python code a print() function is defined. Inside this function, a type() function will use, in which a numeric value is passed in the double quotes (" ") as a function parameter. Double quotes are normally used for print value as a message but in this code, value is not printed because we use the type() function.
- The type() function Returns the parameter class type of the argument(object).
- This function is used for debugging. In this function, we pass a single parameter that will return the type of given object.
The packet is
dropped or discarded. By default, a router will send packets
to a network that has been listed in the routing table. If it happens that the
network is not listed, the packet will be discarded or dropped. Packets that do
not have a default route or gateway of last resort are dropped.
Answer:
B. {1, 2, 2, 3, 3, 4, 5}
Explanation:
Given
The above code segment
Required
Determine which list does not work
The list that didn't work is 
Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3
All other list do not have consecutive duplicate numbers
Option B can be represented as:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 2](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%202)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 3](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%203)
![nums[5] = 4](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%204)
![nums[6] = 5](https://tex.z-dn.net/?f=nums%5B6%5D%20%3D%205)
if (nums.get(j).equals(nums.get(j + 1)))
The above if condition checks for duplicate numbers.
In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:
![nums[0] = 1](https://tex.z-dn.net/?f=nums%5B0%5D%20%3D%201)
![nums[1] = 2](https://tex.z-dn.net/?f=nums%5B1%5D%20%3D%202)
![nums[2] = 3](https://tex.z-dn.net/?f=nums%5B2%5D%20%3D%203)
![nums[3] = 3](https://tex.z-dn.net/?f=nums%5B3%5D%20%3D%203)
![nums[4] = 4](https://tex.z-dn.net/?f=nums%5B4%5D%20%3D%204)
![nums[5] = 5](https://tex.z-dn.net/?f=nums%5B5%5D%20%3D%205)
The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.
<em>This is so because of the way the if statement is constructed.</em>
Answer:
The answer is "option B".
Explanation:
In the given code, four double variable "len1, len2, len3, and total" is declared, in which the first three variables accept some value, and in the total variable, we add those variable. In the next step, an integer variable minLength is defined, which converts the decimal value to an integer and adds the value that is "0.5". In this section, the code uses as an intended purpose but only if the total of 3 lengths is equivalent to or larger then 0.5, and wrong choices can be described as follows:
- In option A, It accepts the negative value, that's why it is wrong.
- Option C, Option D, and Option E all were wrong because the code segment is work as intended.