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klemol [59]
3 years ago
8

Question: Find the volume of the prism. Please help!

Mathematics
2 answers:
MAXImum [283]3 years ago
8 0

Answer:

366 in^3

Step-by-step explanation:

Andrew [12]3 years ago
5 0

I believe that would be 1025.4cm³

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taurus [48]

The answer is A. The Associative Property, followed by the Associative Property.

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3 years ago
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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Can someone please explain to me why and how this equates to 7.4%??????
Mumz [18]

so, you're correct, it is the Food industry, and it went down from 2.7 to 2.5, well, so it really went down 2.7 - 2.5 or 0.2.


well, if we take 2.7 to be the 100% from that row, what is 0.2 off of it in percentage format?


\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 2.7&100\\ 0.2&x \end{array}\implies \cfrac{2.7}{0.2}=\cfrac{100}{x}\implies x=\cfrac{0.2\cdot 100}{2.7}\implies x\approx\stackrel{\%}{7.4}

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2 years ago
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mrs_skeptik [129]
18 mins it is ! I think your missing the question tho
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8 0
3 years ago
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