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andre [41]
3 years ago
14

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an ho

urly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford. Let HHH represent the whole number of hours that the plumber works.
Mathematics
1 answer:
Bess [88]3 years ago
7 0

Answer:

<h2> Anand can afford is 6hours</h2>

Step-by-step explanation:

 Let H represent the whole number of hours that the plumber works.

given that the fixed cost is $65

and the hourly cost is $28

also given that Anand has a total of $250 with him

the total cost can be expressed in terms of the number of hours H as

250=65+28H

we can now solve for H

250-65=28H

185=28H

divide both sides by 28

H=185/28

H=6.60714285714

<em>"The plumber only charges for a whole number of hours."</em>

So the number of hours Anand can afford is 6hours

<em />

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The probability that a player will be asked a math question and then a music question is 0.03125

<h3>How to determine the probability?</h3>

The size of the sections are given as:

Music = 0.5

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Others = 1

So, the total size is:

Total = 0.5 + 0.5 + 1 + 1 + 1

Evaluate

Total = 4

The probability of asking a math question is:

P(Math) = 1/4 = 0.25

The probability of asking a music question is:

P(Music) = 0.5/4 = 0.125

The required probability is:

P(Math and Music) = P(Math) * P(Music)

This gives

P(Math and Music) = 0.25 * 0.125

Evaluate

P(Math and Music) = 0.03125

Hence, the probability that a player will be asked a math question and then a music question is 0.03125

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5 0
2 years ago
Factor the Polynomial: 20x³+34x²+6x = ?
Nataly_w [17]

Answer:

2x(5x+1)(2x+3)=0

Step-by-step explanation:

x{20x^2+34x+6}=0

2x(10x^2+17+3)=0

2x(10x^2+15x+2x+3)=0

2x{5x(2x+3)+1(2x+3)}=0

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8 0
3 years ago
Jared creates a number sequence that has a first term of 2 and a second of term of 5. Each term after the second is created by s
dexar [7]

The rule for the sequence is S(n) = 2S(n-1) - S(n-2)

Alternative form: S(n) = S(n-1) + 3

Step-by-step explanation:

In this problem, we know the first two terms of the sequence:

S(1) = 2

S(2) = 5

We are told that each term after the second is created by subtracting the term before the previous term from twice the previous term. In other words, if we call:

S(n) the current term

S(n-1) the previous term

S(n-2) the term before the previous term

This statement translates into the following sequence:

S(n) = 2S(n-1) - S(n-2)

Because we are subtracting the term before the previous term, S(n-2), from twice the previous term, 2S(n-1).

We can apply now the rule to find the first few terms of the sequence after S(1) and S(2):

S(3) = 2S(2) - S(1) = 2(5)-2=10-2 = 8

S(4) = 2S(3) - S(2) = 2(8)-5=16-5 = 11

S(5) = 2S(4) - S(3) = 2(11)-8=22-8 = 14

We notice also that each term of the sequence is just equal to the previous term plus 3, so the sequence can also be written as

S(n) = S(n-1) + 3

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4 0
3 years ago
The double number line shows the price of
Alex777 [14]

Answer:

According to the first image, 1 cupcake costs $1.5.

So, we can use the rule of three to complete the table.

If 1 cupcake costs $1.5, 5 cupcakes would be $1.5(5)=$7.50

And 18 cupcakes would be $1.5(18)=$27.

However, $18 how many cupcakes represent?

\frac{18}{1.5}=12

Therefore, 12 cupcakes costs $18.

So, the table would be:

Cupcakes     Prices

      5             $7.50

     12             $18

     18             $27

8 0
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Correct Answers only please! I only have two attempts on this assignment, and I cannot retake it. I've already tried the answer
Strike441 [17]

Answer: A. x= 5"

Step-by-step explanation:

ORIGINAL/NEW = 11"/7" = 8.5"/x

x = 7" x 8.5"/11" = 59.5"/11 = 5.409 ≅ 5.41"

If we wanted to keep most of the engraving, we would adjust the larger dimension, but we have been asked to adjust one dimension to 5", since it is said that C. x = 5.41 is incorrect

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\textit{\textbf{Spymore}}

4 0
3 years ago
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