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andre [41]
4 years ago
14

Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an ho

urly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford. Let HHH represent the whole number of hours that the plumber works.
Mathematics
1 answer:
Bess [88]4 years ago
7 0

Answer:

<h2> Anand can afford is 6hours</h2>

Step-by-step explanation:

 Let H represent the whole number of hours that the plumber works.

given that the fixed cost is $65

and the hourly cost is $28

also given that Anand has a total of $250 with him

the total cost can be expressed in terms of the number of hours H as

250=65+28H

we can now solve for H

250-65=28H

185=28H

divide both sides by 28

H=185/28

H=6.60714285714

<em>"The plumber only charges for a whole number of hours."</em>

So the number of hours Anand can afford is 6hours

<em />

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