Answer:
1.5
Step-by-step explanation:
the slope formula is y2-y1/x2-x1
so take two given points (I'll use (-1, -5) and (3,1))
1--5/3--1
6/4
1 2/4
1.5
The answer is 19 because you find the missing number which is 3 then you add all of them up and you get 19!
1)
answer is B) second choice
2
----------------------- =
x^2 + 6x + 8
2
= -------------------
(x -2)(x - 4)
if x = 2 and x = 4 then results would be undefined
2)
3x - 1
--------------
x^2 - 4x - 45
3x - 1
= -------------
(x - 9)(x+5)
x can't equal 9 and (-5)
so answer are:
A and D (first and last choices)
3)
answer is B, second choice (GCF 6x^3)
18x^5 - 6x^3 6x^3(3x^2 - 1) 3x^2 - 1
----------------- = ------------------------- = -----------------
12x^4 6x^3(2x) 2x
4)
15x^3 - 10x^2 5x^2 (3x - 2) 3x - 2
-------------------- = ------------------------ = -------------------------
25x^3 5x^2(5x) 5x
answer is B( second choice)
i don't see 5 and 6 but 7 and 8 twice
7)
(x- 7)(2x -6) 2(x-3)
= -------------------------- = --------------------
x (x -7)(x+6) x(x + 6)
answer is B)(second choice)
8)
(2x + 3)(x+8) 2x +3
= ------------------------ = ------------------
(x+8)(x - 8) x - 8
answer is C (third choice)
Answer:
Change in price = 0.154
Step-by-step explanation:
Given that,
The price on Monday = 24.85
The price on Friday = 25.004
We need to find the change in price from Monday to Friday. It can be calculated as follows :
Change = 25.004 - 24.85
= 0.154
So, the required change in the price is equal to 0.154
.
Answer:
<u>The standard error of the mean is 0.444</u>
Step-by-step explanation:
1. Let's review the information given to us for solving the question:
Size of the sample = 25
Mean amount of money spent per day = US$ 18.01
Standard deviation = US$ 2.22
2. For finding the standard error of the mean, we use the following formula:
Standard error = Standard deviation / √Size of the sample
Standard error = 2.22 / √25
Standard error = 2.22 / 5
<u>Standard error = 0.444</u>
3. Interpretation of the standard error:
The standard error is "the standard deviation of the population of values of a sample statistic in a repeated sampling or its estimate".
Thus, the potential for error in the reported result is not more than ± 0.444 (68% confidence) or no more than 1.96 times the standard error (0.444) = ± 0.87 (at 95% confidence).